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3 years ago

I need help.

Mathematics

1 answer:

saul85 [17]3 years ago

5 0

Answer:

Hey you can login in Spain Server if you find difficulty here

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Cubic yards of concrete will be required for 14 parking lot light pole standards

riadik2000 [5.3K]

Using conversion of units and volume of a cylinder, it is found that 23.17 cubic yards of concrete are needed, option D.

The volume of a cylinder of radius r and height h is given by:

$V = \pi r^2h$

In this problem:

We want the volume in cubic yards, thus, the units of radius and height have to be in yards.
32 inches in diameter, thus 16 inches of radius. Since each inch has 0.0278 yards, this is a radius of 0.44 yards, thus $r = 0.44$ .
Height of 8 feet, and since each feet has 0.33 yards, this is a height of 2.67 yards, thus $h = 2.67$
14 poles, thus the volume is multiplied by 14.

Then:

$V = 14\pi(0.44)^2(2.67) = 23.17$

23.17 cubic yards of concrete are needed, option D.

A similar problem is given at brainly.com/question/22789697

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3 years ago

The purpose of this form is so that your employer can withhold the correct amount of federal income tax from your pay.

Jet001 [13]

I-9 form, hope this helps

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3 years ago

4/6x2/3 simplified and in fraction form

Kaylis [27]

Answer:

onvert 234 2 3 4 to an improper fraction. ... Divide each term by −6 - 6 and simplify. ... The result can be shown in multiple forms.

Step-by-step explanation:

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3 years ago

An executive committee consists of 15 members: 7 men & 8 women. 5 members are selected at random to attend a meeting in Hawa

asambeis [7]

Answer:

1.8%

Step-by-step explanation:

(8c5 * 7c0)/15c5

= 0.018

This is the answer which I get when I solve this... cross check the calculations once.

3 0

3 years ago

At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

4 0

4 years ago