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tigry1 [53]
3 years ago
15

585,156.22 nearest thousand

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0
It would be 585 because

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EastWind [94]
Add and subtract: Find Least Common Denominator, multiply out, add/subtract as normal

Multiply: Multiply both top and bottom

Divide: Multiply by reciprocal
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Timed test plz help..T or F
elixir [45]

Answer:

the answer is true

Step-by-step explanation:

hope that helps

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A square Banner has an area of 20 square feet. To the nearest tenth of a foot what is the length of one side of the banner ?
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3 years ago
The expression 210,000\left(1.02\right)^x210,000(1.02)
Bad White [126]

Answer:

The house is increasing in value by 2% each year.

Correct the increase is 1.02 per year the value of b>0 and the percentage of increase each year is:

\frac{1.02-1}{1} *100 = 2\%

Step-by-step explanation:

For this case if we have this expression

210000(1.02)^x

We have the same functional forma like the exponential model given by:

y = a b^x

Where a = 210000 represent the constant or initial value and b = 1.02 represent the base.

So let's analyze the possible options:

The house has a starting value of 1.02.

False the starting value for this case is 210000 since if x=0 then we see that the value is 210000

The house is decreasing in value by 2% each year.

False the increase is 1.02 each year so then in % we have

\frac{1.02-1}{1} *100 = 2\%

We  have an increase of 2% each year

The house is increasing in value by 2% each year.

Correct the increase is 1.02 per year the value of b>0 and the percentage of increase each year is:

\frac{1.02-1}{1} *100 = 2\%

The value of the house is changing by 0.02% each year.

False the increase is 2% per year

4 0
3 years ago
what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
liberstina [14]

The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

4 0
2 years ago
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