Answer:
a). Y = y0e^-k(t)
b) Y = 19.4 Unit mass
Step-by-step explanation:
Y = y0e^-k(t)
Where y is amount present at the time
Y0 is initial amount present at t = 0
Y0 = 58.7
Half life = 5 hours
At half life , y = 58.7/2
At half life , y = 29.35
K = decaying constant.
Let's look fithe value of k
Y = y0e^-k(t)
29.35 = 58.7e^-k(5)
29.35/58.7 = e^-k(5)
0.5 = e^-k(5)
In 0.5 = -k(5)
-0.69314718 = -k(5)
0.138629436 = k
The value present in 8 hours will be
Y = y0e^-k(t)
Y = 58.7e-0.138629436(8)
Y = 58.7e-1.109035488
Y = 58.7(0.329876978)
Y= 19.36377861
To the nearest tenth
Y = 19.4 unit of mass
Answer:
21
Step-by-step explanation:
Answer:
6/23
Step-by-step explanation:
There are 6 males who want ice cream out of the 23 males that are there
Answer:
H'(15, - 7)
Step-by-step explanation:
Given the translation < 10, - 11 >
Add 10 units to the x- coordinate of H and subtract 11 units from the y- coordinate of H, that is
H(5, 4) → H'(5 + 10, 4 - 11) → H'(15, - 7)
We have that what the air within the box weigh is mathematically given as
m=9.8kg
From the question we are told
If a box has a sea-level air density of 1.24 kg * m ^ - 3 how much would the <em>air </em>within the box weigh?
<h3>Arithmetics</h3>
Generally the equation for the Mass is mathematically given as
M=d*V
Therefore
m=1.24*8
m=9.8kg
Weight
m*
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