Answer: d+q= 2.55
or d=15+q
I believe this is how you do it
Step-by-step explanation:
First equal the equation to f(x) or y
f(x)= (x²+x-2)÷(x²-3x-4)
To find y-intercept, x coordinates have to be 0
f(0)=(0²+0-2)÷(0²-3(0)-4)
f(0)=-2/-4
f(0)=1/2 (y-intercept)
To find x-intercept, make y=0
0=(x²+x-2)÷(x²-3x-4)
0((x²-3x-4)=(x²+x-2)
0=x²+x-2
0=(x-1)(x+2)
x-1
x-1=0
x=1
x+2=0
x=-2
The x-intercepts would be 1, -2
Hope I helped :)
Answer:
3280 square inches
Step-by-step explanation:
The surface area of square pyramid = 4* the area of the triangular side + the area of the square base.
TRIANGULAR SIDE
The pyramid has an isosceles triangular side of size, a=40 inches, b= 29 inches, c = 29 inches.
Surface area = sqrt{ s(s-a)(s-b)(s-c) }
Where s= (a+b+c)/2
S= (40+29+29)/2 = 49
Surface area = sqrt{ 49(49-40)(49-29)(49-29)}
Surface area = 420 square inches
SQUARE BASE
Area of a square = a²
Area = 40² = 1600 square inches
Surface area of the pyramid = 4*420 + 1600 = 1680 + 1600
Surface area = 3280 square inches.
