I would solve the first equation for x and then sub that value into x in the second equation. That's the easiest way. x - 2y = 3 solved for x is x = 2y+3. Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2. 13y = -13, and y = -1. Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1. Therefore, your solution to this system is (1, -1), first choice above.
Answer:
The graph of f has an inflection point at x = 0.
Step-by-step explanation:
An inflection point occurs when the second derivative changes signs. Since f"(x) is decreasing and has an x-intercept at 0, it changes signs from + to -, so there is an inflection point at x = 0.
B because it u and 9 friends each want the same amount from splitting 1.30 which gives you .13
Answer:
No, because it fails the vertical line test ⇒ B
Step-by-step explanation:
To check if the graph represents a function or not, use the vertical line test
<em>Vertical line test:</em> <em>Draw a vertical line to cuts the graph in different positions, </em>
- <em>if the line cuts the graph at just </em><em>one point in all positions</em><em>, then the graph </em><em>represents a function</em>
- <em>if the line cuts the graph at </em><em>more than one point</em><em> </em><em>in any position</em><em>, then the graph </em><em>does not represent a function </em>
In the given figure
→ Draw vertical line passes through points 2, 6, 7 to cuts the graph
∵ The vertical line at x = 2 cuts the graph at two points
∵ The vertical line at x = 6 cuts the graph at two points
∵ The vertical line at x = 7 cuts the graph at one point
→ That means the vertical line cuts the graph at more than 1 point
in some positions
∴ The graph does not represent a function because it fails the vertical
line test