Answer:
-3 is the answer because if we divide 15 by 5 we get 3 . So it is same only the question is -15 divide by 5 so the answer is -3
1.) f(x)=7(b)^x-2
x=0→f(0)=7(b)^0-2=7(1)-2=7-2→f(0)=5→(x,f(x))=(0,5) Ok
2.) f(x)=-3(b)^x-5
x=0→f(0)=-3(b)^0-5=-3(1)-5=-3-5→f(0)=-8→(x,f(x))=(0,-8) No
3.) f(x)=5(b)^x-1
x=0→f(0)=5(b)^0-1=5(1)-1=5-1→f(0)=4→(x,f(x))=(0,4) No
4.) f(x)=-5(b)^x+10
x=0→f(0)=-5(b)^0+10=-5(1)+10=-5+10→f(0)=5→(x,f(x))=(0,5) Ok
5.) f(x)=2(b)^x+5
x=0→f(0)=2(b)^0+5=2(1)+5=2+5→f(0)=7→(x,f(x))=(0,7) No
Answers:
First option: f(x)=7(b)^x-2
Fourth option: f(x)=-5(b)^x+10
Edges that are perpendicular to PR basically means what edges make a 90° angle with PR.
Those edges are HP , RA, TR and QP.
Hence, the answer is A, B and C.
12,5,13 are Pythagorean triplets..
so, missing side will be 12 inches
hope it helps
Hyp^2 = Base^2 + perpendicular^2
2 solutions, the root to the equation is the same as the root to the solution also known as “double roots”
