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Mathematics

1 answer:

ozzi3 years ago

6 0

Answer:

5 inches

Step-by-step explanation:

Theorem states that the smaller two sides of a triangle have to be greater than the biggest side.

The least possible answer would be 5 inches.

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Identify the vertex for the graph of y = 2x2 + 8x − 3. (2, 21) (2, 17) (−2, −11) (−2, −27)

Finger [1]

$\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
\begin{array}{lcccl}
y = & 2x^2& +8x& -3\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad 
\left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left( -\cfrac{8}{2(2)}~~,~~-3-\cfrac{8^2}{4(2)} \right)\implies \left( \cfrac{-8}{4}~~,~~-3-\cfrac{64}{8} \right)
\\\\\\
\left(-2~~,~~-3-8 \right)\implies (-2~~,~~-11)$

5 0

4 years ago

Read 2 more answers

The point A(-2, 3) is translated using T: (x,y) = (x + 4, y + 2).

Charra [1.4K]

Answer: Choice D) $2\sqrt{5}$

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Work Shown:

Point A starts at (-2,3) and moves to (2,5) after applying the translation rule of "shift 4 to the right, 2 up".

Use the distance formula to find the distance from (-2,3) to (2,5)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-2-2)^2 + (3-5)^2}\\\\d = \sqrt{(-4)^2 + (-2)^2}\\\\d = \sqrt{16 + 4}\\\\d = \sqrt{20}\\\\d = \sqrt{4*5}\\\\d = \sqrt{4}*\sqrt{5}\\\\d = 2\sqrt{5}\\\\d \approx 4.472136\\\\$