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Romashka-Z-Leto [24]
3 years ago
10

I NEED HELP QUICK #33 #34 #35

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0

Answer:

34.) 93 + 72 = 165

x = 165

35.) w + z + 9(w - z)

w + z + 9w - 9z

w + 9w + z - 9z

10 w - 8z

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NEED HELP FAST ON THESE 2 questions
Fofino [41]

Answer:

hope it helped u a lot

Step-by-step explanation:

plss give me braniest

7 0
2 years ago
In a study researchers reported the mean BMI for men 60 and older to be 24.7 with a standard deviation of 3.3 and the mean BMI f
erica [24]

Answer:

Probability that the difference in the mean BMI (men-women) for 45 women and 50 men selected independently and at random will exceed 2.1 = 0.2451

Step-by-step explanation:

The central limit theorem helps us to obtain the mean and the standard deviation of any sampling distribution.

Given that the sample was obtained from a normal distribution or an approximately normal distribution & it was obtained using random sampling techniques with each variable independent of one another and with each sample with adequate sample size,

Mean of sampling distribution (μₓ) = Population mean (μ)

Standard deviation of the sampling distribution = σₓ = (σ/√N)

where σ = population mean

N = Sample size

For the 45 women

μₓ = μ = 23.1

σₓ = (σ/√N) = (3.7/√45) = 0.552

For the 50 men

μₓ = μ = 24.7

σₓ = (σ/√N) = (3.3/√50) = 0.467

To find the probability that the difference in the mean BMI (men-women) for 45 women and 50 men selected independently and at random will exceed 2.1, we need to combine the distributions.

New distribution = (BMI of men) - (BMI of women) = x = X₁ - X₂

When independent distributions are combined, the combined mean and combined variance are given through the relation

Combined mean = Σ λᵢμᵢ

(summing all of the distributions in the manner that they are combined)

Combined variance = Σ λᵢ²σᵢ²

(summing all of the distributions in the manner that they are combined)

λ₁ = 1, λ₂ = -1

μ₁ = 24.7, μ₂ = 23.1

σ₁ = 0.467, σ₂ = 0.552

Combined mean = (Mean of men) - (Mean of women) = 24.7 - 23.1 = 1.6

Combined Variance = (1²×0.467²) + [(-1)²×(0.552²)] = 0.522793

Combined standard deviation = √0.522793 = 0.723

Probability that the difference in the mean BMI (men-women) for 45 women and 50 men selected independently and at random will exceed 2.1 = P(x > 2.1)

Note that the resulting distribution from the combination of distributions is still a normal distribution since the distributions combined were normal distributions too.

Hence, we first normalize or standardize 2.1

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (2.1 - 1.6)/0.723 = 0.69

To determine the required probability

P(x > 2.1) = P(z > 0.69)

We'll use data from the normal distribution table for these probabilities

P(x > 2.1) = P(z > 0.69) = 1 - P(z ≤ 0.69)

= 1 - 0.7549

= 0.2451

Hope this Helps!!!

6 0
3 years ago
Dylan has 128 prices of candy from Halloween . he eats half of his candy each week.
Scilla [17]

Answer:

55.5 left over.

Step-by-step explanation:

128/2 = 64

half each week so;

1 whole = two weeks

8 weeks = 8

+ 1 = 8 1/2

so, 64/8.5

is going to be 55.5 left.

5 0
2 years ago
Round 46,750 to the nearest thousand.
Salsk061 [2.6K]

Answer:

47,000

Step-by-step explanation:

6,750 rounds up to 7,000

5 0
2 years ago
Can someone help me with this please
erastova [34]

Not positively sure but I believe it goes like this

Answer: 9x+26+5x=180

14x+26=180

180-26=14x

14x=154

X=15

8 0
2 years ago
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