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Serhud [2]
3 years ago
10

I need answers to this

Mathematics
1 answer:
ololo11 [35]3 years ago
5 0

Answer:

x = -5, and y = -6

Step-by-step explanation:

Suppose that we have two equations:

A = B

and

C = D

combining the equations means that we will do:

First we multiply both whole equations by constants:

k*(A = B) ---> k*A = k*B

j*(C = D) ----> j*C = j*D

And then we "add" them:

k*A + j*C = k*B + j*D

Now we have the equations:

-x  - y = 11

4*x - 5*y = 10

We want to add them in a given form that one of the variables cancels, so we can solve it for the other variable.

Then we can take the first equation:

-x  - y = 11

and multiply both sides by 4.

4*(-x - y = 11)

Then we get:

4*(-x - y) = 4*11

-4*x - 4*y = 44

Now we have the two equations:

-4*x - 4*y = 44

4*x - 5*y = 10

(here we can think that we multiplied the second equation by 1, then we have k = 4, and j = 1)

If we add them, we get:

(-4*x - 4*y) + (4*x - 5*y) = 10 + 44

-4*x - 4*y + 4*x - 5*y = 54

-9*y = 54

So we combined the equations and now ended with an equation that is really easy to solve for y.

y = 54/-9 = -6

Now that we know the value of y, we can simply replace it in one of the two equations to get the value of x.

-x - y = 11

-x - (-6) = 11

-x + 6 = 11

-x = 11 -6 = 5

-x = 5

x = -5

Then:

x = -5, and y = -6

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John has × marbles and max has twice as many.max give gives john 5 of his marbles does max now have
rjkz [21]

Answer: 2x -5

Step-by-step explanation:

Hi, to answer this question we have to write equations with the information given:

  • <em>John has × marbles  </em>

John=x

  • <em>Max has twice (multiplied by 2) as many.max give gives john 5 of his marbles. </em>

We have to multiply by 2 the number of marbles that John has (x), and subtract 5.  

Max = 2x -5

Feel free to ask for more if needed or if you did not understand something.  

8 0
3 years ago
Choose one of the factors of x^3 + 343.
Debora [2.8K]

First, note that 343=7^3. Then use the formula for the sum of perfect cubes:

a^3+b^3=(a+b)(a^2-ab+b^2).

Therefore,

x^3 + 343=x^3+7^3=(x+7)(x^2-7x+49).

The quadratic trinomial x^2-7x+49 couldn't be factored anymore, so the expression x^3 + 343 has two factors x+7 and x^2-7x+49.

Answer: correct choice is A.

3 0
3 years ago
I don't understand how to further answer the question. Can somebody explain with an image of the work??
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What does diagonal DB equal?<br><br>• 4<br>• 3<br>• 6<br>• 7​
dimaraw [331]

Answer:

<h2>|DB| = 6</h2>

Step-by-step explanation:

If ABCD is a rhombus then the diagonals AC and BD are perpendicular and intersect in half.

Let E be the point of intersection of the diagonals.

Therefore:

AE ≅ EC and DE ≅ EB ⇒ |AE| = |EC| and |DE| = |EB|.

DB = DE + EB

|EB| = 3 ⇒ |DB| = 3 + 3 = 6

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