I'm assuming you meant to write a^4 = 625.
If that is the case, then note how 625 = 25^2, and how a^4 is the same as (a^2)^2
So we go from this
a^4 = 625
to this
(a^2)^2 = 25^2
Apply the square root to both sides and you'll end up with: a^2 = 25
From here, apply the square root again to end up with the final answer: a = 5 or a = -5
As a check:
a^4 = (-5)^4 = (-5)*(-5)*(-5)*(-5) = 25*25 = 625
a^4 = (5)^4 = (5)*(5)*(5)*(5) = 25*25 = 625
Both values of 'a' work out
Graph B shows 85% since it is shaded in, and 93% is open
Answer: ![b=13/8](https://tex.z-dn.net/?f=b%3D13%2F8)
<u>Cross multiply</u>
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<u>Flip the equation</u>
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<u>Divide both sides by 8</u>
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<u>Step-by-step explanation:</u>
Here we have , an expression c + 2 . We need to find that What happens to the value of the expression c+2 as c increases .Let's find out:
Let y = c + 2 or
, where y is dependent on c and y is directly proportional to c i.e. as value pf c increase value of y increases . Let's have some example as
At c = 1
![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = 1+2](https://tex.z-dn.net/?f=y%20%3D%201%2B2)
⇒ ![y = 3](https://tex.z-dn.net/?f=y%20%3D%203)
At c = 2
![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = c+2](https://tex.z-dn.net/?f=y%20%3D%20c%2B2)
⇒ ![y = 2+2](https://tex.z-dn.net/?f=y%20%3D%202%2B2)
⇒ ![y = 4](https://tex.z-dn.net/?f=y%20%3D%204)
So , value of expression c+2 increases with value of c . Also , expression c+2 is a straight line having a slope of 1 and a y-intercept of 2 .
1. so just subsitute numbers if we subsitute 5 for x then we get 0 if it's height is 6 then the time will be 16
2. so you want to factor the equation and get f(x)=x^2-4x-5=(x-5)(x+1) then set this equation = to 0 so (x-5)(x+1)=0
x-5 or x+1 must equal 0 so
x-5=0
x=5
x+1=0
x=-1
discard this because you cannot yield a negative ammount
so when the bank yields 5 in a day, the income is 0