All categories

3 years ago

Evaluate the following numerical expression (6+ 3) ÷ (4 - 5) =

Mathematics

1 answer:

Dvinal [7]3 years ago

5 0

<em />

Because you do what’s in parentheses first which is (6+3)

You get the answer 9

Then you do 4-5 which will lead to going into negative numbers and the answer will be -1

So 9/-1 or Nine divided by negative one

You might be interested in

64 percent of the animals shelter are dogs about what fraction of the animals at the shelter are dogs

Lilit [14]

I think it would be 64/100 because 64 percent is most likely out of 100 percent

3 0

3 years ago

Triangles P and Q are similar.

svp [43]

Answer:

if i labeled the triangle correctly BC= sqrt 97, ZX=32sqrt 2

Step-by-step explanation:

join my stream and tell me how to label the triangle

(ChildOfHermes)

6 0

2 years ago

Help please :))<br>10 points

DaniilM [7]

Answer:

54 -3n²

Step-by-step explanation:

The square of a number (n) is represented by n². Three times that value is represented by 3n².

The relation "a is subtracted from b" is represented as ...

b - a

When 3n² is subtracted from 54, the appropriate representation is ...

54 -3n²

6 0

3 years ago

15600=x (x+1)(x+2) What is x?

Andrew [12]

The answer is x = 24

4 0

3 years ago

Read 2 more answers

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

3 years ago

Read 2 more answers

Evaluate the following numerical expression (6+ 3) ÷ (4 - 5) =​

Evaluate the following numerical expression (6+ 3) ÷ (4 - 5) =