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larisa [96]
2 years ago
9

Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.

There are 15 questions on the test and the students have been given 55 minutes to complete it. Which value could replace x in the table?
a.7 – m
b.23 – m
c.8(15 – m)
d.8(15) – m
Mathematics
1 answer:
kakasveta [241]2 years ago
4 0

Answer:

It would be 8(15-m)

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liberstina [14]
The second one is correct
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There are 63 female performers in a dance recital. the ratio of men to women is 5:9. how many men are in the dance recital?
valentinak56 [21]
In d ratio 5:9 which equals 5+9=14
the total female performers is 63
For men = 5/14*63=5/2*9
=45/2 =22.5
The men would be about 22.5 in the dance recital
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Can 4,9, 15 represent the lengths of the sides of a triangle?
Gwar [14]

Answer:

No

Step-by-step explanation:

4,4,5 and 12,7,7 are isosceles triangles because they have two equal sides . 15,15,15 is an equilateral triangle -it has three equal sides

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Plz need answer need for grades
Igoryamba

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15

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A company manufactures and sells x television sets per month. The monthly cost and​ price-demand equations are ​C(x)=72,000+60x
myrzilka [38]

Answer:

Step-by-step explanation:

Given

Cost Price c(x)=72000+60x

Price p(x)=300-\frac{x}{20}

Revenue generated R(x)=P(x)\times x

where x=no of units

R(x)=300x-\frac{x^2}{20}

To get maxima and minima differentiate R(x)

\frac{\mathrm{d} R(x)}{\mathrm{d} x}=0

\frac{\mathrm{d} R(x)}{\mathrm{d} x}=300-2\times \frac{x}{20}=0

300=2\times \frac{x}{20}

x=3000

maximum Revenue R(x)=(300-\frac{300}{20})\times 300=4,50,000

(b)Profit=Revenue - cost

Profit=xp(x)-c(x)

Profit=300x-\frac{x^2}{20}-72000-60x

Profit(z)=240x-\frac{x^2}{20}-72000

differentiate Profit to get maximum value

\frac{\mathrm{d} z}{\mathrm{d} x}=240-2\times \frac{x}{20}

x=2400

maximum Profit z=2,16,000

(c)Now company decided to tax the company $ 55 for each set

Profit (z_1)=xp(x)-c(x)-55x

z_1=300x-\frac{x^2}{20}-72000x-60x^2-55x

z_1=185x-\frac{x^2}{20}-72,000

differentiate Profit to get maximum value

\frac{\mathrm{d} z_1}{\mathrm{d} x}=0

\frac{\mathrm{d} z_1}{\mathrm{d} x}=185-\frac{2x}{20}=0

x=1850

P(z_1\ at\ x=1850)=99125

company should charge 207.5 $ for each set

         

6 0
3 years ago
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