A(0,-1)
B(3√3/3, 2)
Slope of AB = (y₂ - y₁)/(x₂-x₁)
Slope = (2-1)/(√3/3 , -0)
Slope = 1/√3/3 = 1/√3 = √3/3
OR SLOPE = tan(a°) = √3/3 and a° = 30°
Answer:
6
Step-by-step explanation:
first take 3+3=6+12=18+28=46+7=53+12=65
65-60=5 five is answer
Solution is Y= -12 for your question
Answer: 22 small snow cones and 34 large snow cones were sold.
Step-by-step explanation:
Let x represent the number of small snow cones that were sold.
Let y represent the number of large snow cones that were sold.
Selena's snow cone stand sells small snow cones for $2 and large snow cones for $3.50. One summer day, she sold $163 worth of snow cones. This means that
2x + 3.5y = 163 - - - - - - - - - - 1
If the number of large snow cones sold was 12 more than the number of smalls snow cones, it means that
y = x + 12
Substituting y = x + 12 into equation 1, it becomes
2x + 3.5(x + 12) = 163
2x + 3.5x + 42 = 163
5.5x = 163 - 42
5.5x = 121
x = 121/.5 = 22
y = x + 12 = 22 + 12
y = 34
Answer:
78.383%
Step-by-step explanation:
The pH of randomly selected swimming pools follows a normal distribution with mean 7.4 and standard deviation 0.22. A pool should have a pH between 7.2 and 7.8 so that chlorine treatment is effective.
Using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = 7.2
z = 7.2 - 7.4/0.22
z = -0.90909
Probability value from Z-Table:
P(x = 7.2) = 0.18165
For x = 7.8
z = 7.8 - 7.4/0.22
z = 1.81818
Probability alue from Z-Table:
P(x = 7.8) = 0.96548
The probability of pools having an acceptable pH level(7.2 and 7.8)
= P(x = 7.8) - P(x = 7.2)
= 0.96548 - 0.18165
= 0.78383
Converting to percentage
0.78383 × 100
= 78.383%
The percentage of pools having an acceptable pH level is 78.383%
