The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Answer:
D. $7/hour
Step-by-step explanation:
128-86=42
42/6=7
Answer:To find a scale factor between two similar figures, find two corresponding sides and write the ratio of the two sides. If you begin with the smaller figure, your scale factor will be less than one. If you begin with the larger figure, your scale factor will be greater than one.
Step-by-step explanation : )
Answer:
Step-by-step explanation:
6x + 3y = 3 simplify by dividing both sides by 3 2x + y = 1
3x - y = 4 the 1st equation has a positive y, the 2nd has a negative y. Use elimination
to reduce them down to a single variable equation:
2x + y = 1
3x - y = 4
________
5x = 5 solve
X = 1 substitute back in to one of the original equations to find y
3x - y = 4
3(1) - y = 4
- y = 1
y = -1 (1,-1)
Multiples of 12: 12, 36, 48, 60
