The dog house consists of two geometric objects, triangular prism and rectangular prism.
First, find the surface area of triangular prism
The triangular prism consists of
base of triangle (b) = 3 ft
height of triangle (h) = 2.5 ft
height of prism or length of rectangle (l) = 4 ft
side of triangle or width of rectangle (w) = 2.5 ft
Now, calculate the area
area of tp = area of two triangle + area of 2 rectangle
area of tp = (2 × 1/2 × b × h) + (2 × l × w)
area of tp = (2 × 1/2 × 3 × 2) + (2 × 4 × 2.5)
area of tp = 6 + 20
area of tp = 26 ft²
Second, find the surface area of rectangular prism
The rectangular prisms consists of
length (l) = 3 ft
width (w) = 4 ft
height (h) = 2 ft
Now, calculate the area
area of rp = area of back and front rectangle + area of left and right rectangle
area of rp = (2 × l × h) + (2 × w × h)
area of rp = (2 × 3 × 2) + (2 × 4 × 2)
area of rp = 12 + 16
area of rp = 28 ft²
Third, add both of the area
area = area of tp + area of rp
area = 26 + 28
area = 54 ft²
The area of the dog house is 54 ft²
Answer:
b
Step-by-step explanation:
A=40
Step-by-step explanation:
A= b×h÷2
A=10×8÷2
A=80÷2
A=40
Answer:
Q matches to a and P matches to b
Step-by-step explanation:
This is a volume question so we can use the volume of a cylinder to see which one corresponds to what. Volume of a cylinder is 
h. We know that the heights of the cylinders are the same since the diagram says so. We also know pi is the same since thats a constant. The only thing thats different is the radius (as you can see radius of P is bigger than Q). If the radius of P is bigger than Q and all the other things are the same (height is the same and pi is the same), then that automatically means that P has more volume than Q. More volume means more time to fill up. Since Q has less volume, it will take less time to fill up. So now we look at the graph. A shows that the height of water increases at a faster rate than that of B. This is because there is less volume in that container (less volume=less time to fill up). Therefore a matches to Q and therefore b matches to P
