5 and 2/3 divided by 4?
2 answers:
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Answer:
- <u><em>The height of the missing rectangle is 0.15</em></u>
Explanation:
The image attached has the mentioned <em>histogram</em>.
Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.
Only the rectangle for the class [3,4] is missing.
The height of each rectangle is the relative frequency of the corresponding class.
The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.
In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.
<u>1. Sum of the known relative frequencies</u>:
- 0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85
<u>2. Missing frequency</u>:
- 1 - 0.85 = 0.15
<u>3. Conclusion</u>:
- The height of the missing rectangle is 0.15
Answer:
Option A
Step-by-step explanation:
Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF
Area of ΔABH =
=
= 9 in²
Area of the trapezoid =
=
= 25 in²
Area of ΔDEF =
= 24 in²
Therefore, area of the given figure = 9 + 25 + 24
= 58 in²
Option A will be the correct option.
