answer c. none of the above
<span>Let us start with the schnauzers, the easiest one to imagine. Let us assume that there were x number of schnauzers.
Scottie's are 3 more than schnauzers. So their number is x+3
Wire haired terriers are 5 less than twice the number of schnauzers.
So their number is 2x -5 (2x for twice the number of schnauzers)
Now add all these numbers.
That is x + x+3 + 2x-5 = 4x -2
The total number of dogs, 78, is given in the question
Now we know that 4x -2 =78
4x = 78 +2
= 80
Therefore x = 80/4
= 20.
So there were 20 schnauzers, 23 Scottie’s and 35 wire haired terriers</span>
Answer:
We have a + b as;
2 + 3 = 5
Step-by-step explanation:
Here, we want go get the value of a and b
from the second equation, we can get an expression for b
We have this as;
7a - b = 11
Thus,
b = 7a - 11
Now, from here, we can substitute the value of b into the first equation
We have this as;
5a + 4(7a - 11) = 22
5a + 28a -44 = 22
33a = 22 + 44
33a = 66
a = 66/33
a = 2
Recall;
b = 7a - 11
substituting the value of a from above;
b = 7(2) - 11
b = 14 - 11
b = 3
Answer:
80km --- 49.7097mi
Step-by-step explanation:
thats quite slow... but please provide context then i can solve it for you
I am slightly confused. What exactly is the question?
