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weeeeeb [17]
3 years ago
6

The "HOPE PROBE " launched by Abu Dhabi weighed 1350 Kg along with the fuel it carried . If it uses 576 Kg of fuel during its jo

urney, can you find its present weight ?
Mathematics
1 answer:
dedylja [7]3 years ago
3 0

Answer: 774 kg

Step-by-step explanation:

Given

Dhabi weighted 1350 kg

It uses 576 kg of fuel during its journey

So, the remaining fuel is given by the difference of initial and used fuel present i.e.

\Rightarrow 1350-576=774\ kg

The present weight is 774 kg

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Lenora buys 3.7 lbs of potatoes that cost $0.29 per pound. How much does she pay for the potatoes. Round to nearest cents
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Halp meh ples friends :D​
Katen [24]

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Step-by-step explanation:

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3 years ago
Quadrilateral QRST is inscribed in circle W as shown below. The measure of ∠QRS is 12 degrees less than three times the measure
Tju [1.3M]

<u>Corrected Question</u>

Quadrilateral QRST is inscribed in circle W as shown below. The measure of ∠QRS is 12 degrees less than three times the measure of ∠QTS and

mRQT=mRST .

(a)Determine the measure of Angle QTS .

(b)What is the common measure of angles RQT and RST ?

Answer:

(a)48 degrees

(b)90 degrees

Step-by-step explanation:

Theorem: Opposite angles of a cyclic quadrilateral are supplementary.

(a)

Let the measure of ∠QTS=x

Therefore: m∠QRS=3x-12

∠QTS and ∠QRS are opposite angles of a cyclic quadrilateral. By the theorem above:

x+3x-12=180

4x=180+12

4x=192

x=48 degrees

The measure of angle QTS is 48 degrees.

(b)Since mRQT=mRST

mRQT and mRST are opposite angles of a cyclic quadrilateral

Therefore:

mRQT+mRST=180 degrees

2mRQT=180

mRQT=90 degrees

Therefore, the common measure of RQT and RST is 90 degrees.

6 0
3 years ago
If five times the smaller of two numbers is subtracted from twice the larger the result is 16 if the larger is increased by thre
Rudiy27

Answer:

Smaller Number = 10

Larger Number = 33

Step-by-step explanation:

Let the smaller number be "x" and the larger number be "y"

5 TIMES smaller is SUBTRACTED from TWICE larger, the result is 16, we can write:

2y - 5x = 16

and

Larger increased by 3 TIMES SMALLER, result is 63, so we can write:

y + 3x = 63

We can write this in terms of x, as:

y = 63 - 3x

Now we put this in equation 1 and solve for x first:

2y - 5x = 16

2(63 - 3x) - 5x = 16\\126-6x-5x=16\\11x=110\\x=10

Now,

y = 63 - 3x

y = 63 - 3(10)

y = 63 - 30

y = 33

Smaller Number = 10

Larger Number = 33

8 0
3 years ago
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