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Olenka [21]
3 years ago
10

Find the area of the shaded region:

Mathematics
1 answer:
Deffense [45]3 years ago
6 0

Answer:

34560

Step-by-step explanation:

You have to multiply to get your answer

Hope I'm right...

Hope this helps plz like and brainly :D

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What is -2 times 3 divide by 2 times 2 plus 2 minus 2 times 2
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-2 * 3 = -6.
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-4 - 2= -6
-6 * 2 = -12.

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Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing,
erma4kov [3.2K]
<span>The y-intercept of  is  .
Of course, it is 3 less than  , the y-intercept of  .
Subtracting 3 does not change either the regions where the graph is increasing and decreasing, or the end behavior. It just translates the graph 3 units down.
It does not matter is the function is odd or even.

 is the mirror image of  stretched along the y-direction.
The y-intercept, the value of  for  , is</span><span>which is  times the y-intercept of  .</span><span>Because of the negative factor/mirror-like graph, the intervals where  increases are the intervals where  decreases, and vice versa.
The end behavior is similarly reversed.
If  then  .
If  then  .
If  then  .
The same goes for the other end, as  tends to  .
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4 0
3 years ago
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1.Parallelogram ACFD is split in two parts so that ABED and FEBC are congruent isosceles trapezoids. What are the measures of al
DiKsa [7]
Refer to the diagram shown below.

Because ACFD is a parallelogram, its opposite angles are equal. Therefore
x = m∠ACF = m∠BCF = 48°  
Similarly,
y = m∠CAD = m∠CFD 

The sum of the angles inside a parallelogram is 360°. Therefore
48° + x + y + y = 360°
Because x = 48°,
48° + 48° + 2y = 360°
2y = 360° - 96° = 264°
y = 132°

Because ABED and FEBC are congruent, therefore
y = m∠DAB = m∠CFE = 132°
x = m∠ADE = m∠FCB = 48°

Because FEBC is a parallelogram, the opposite angles are equal. Therefore
m∠CBE = m∠CFE = y = 132°
m∠BCF = m∠BEF = x = 48°

Answer:
The measures of all angles of trapezoid FEBC are
m∠BCF = 48°
m∠BEF = 48°
m∠CBE = 132°
m∠CFE = 132°

7 0
3 years ago
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