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BartSMP [9]
2 years ago
15

PLEASE HELP! Evaluate the expression 5(7 − 4)2 ÷ 3 + 11.

Mathematics
2 answers:
Semenov [28]2 years ago
8 0
35-20x2divide3+11
15x2
30divide3=10
10+11=21
nataly862011 [7]2 years ago
5 0

Answer:

26

Step-by-step explanation:

5(7 − 4)^2 ÷ 3 + 11.

PEMDAS says parentheses first

5(3)^2 ÷ 3 + 11.

Then exponents

5 (9)÷ 3 + 11.

Multiply and divide from left to right

45 ÷ 3 + 11

15 +11

26

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guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

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3 0
1 year ago
The height of a triangle is 7m less than it’s base the area of the triangle is 30m^2 what is the length of the base what is the
Ksju [112]
If you know the base and area of the triangle, you can divide the base by 2, then divide that by the area to find the height. To find the height of an equilateral triangle, use the Pythagorean Theorem, a^2 + b^2 = c^2.
3 0
3 years ago
2 1/2 divided by 2 1/3
horsena [70]

Answer:

Exact Form: 15/2

Decimal Form: 7.5

Mixed Number Form: 7 1/2

Step-by-step explanation:

4 0
2 years ago
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To prove that ΔAED ˜ ΔACB by SAS, Jose shows that StartFraction A E Over A C EndFraction = StartFraction A D Over A B EndFractio
Ira Lisetskai [31]

Answer:

A on Edg.

Step-by-step explanation:

Took the Test

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3 years ago
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In the data set below, what is the interquartile range?<br> 7<br> 1<br> 5<br> 5<br> 9<br> Submit
Marizza181 [45]

Answer:

5

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1  5  5  7  9 ← data in ascending order

       ↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1  5

 ↑ lower quartile = \frac{1+5}{2} = 3

The upper quartile is the middle value of the data to the right of the median.

7  9

 ↑ upper quartile = \frac{7+9}{2} = 8

Thus

interquartile range = 8 - 3 = 5

3 0
2 years ago
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