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4 years ago

Which statement MUST be true?

Mathematics

1 answer:

romanna [79]4 years ago

7 0

The answer is C

The reason being these two sets of angles are opposite angles (also known as vertical angles) and opposite angles are always congruent.

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Graph f(x)=5x– 45. Show me on a graph

Wewaii [24]

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Just Try ur best

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3 years ago

You have a credit card that has a balance of $3,589.90 and a credit limit of $5,000. How much is the balance over the acceptable

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4 years ago

Ice cream cost $4.96 for 4 litres how much for 6 litres

aivan3 [116]

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$7.44

Step-by-step explanation:

$4.96/ 2= 2.48

$2.48 X 3 = 7.44

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3 years ago

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I need help on My homework help me

Sladkaya [172]

Answer: $1,007.00

I hope this helps, and Happy Holidays! :)

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3 years ago

Please solve with full steps (only question 6)

Stels [109]

Answer:

$\large \boxed{\sf \ \ k=1 \ \ }$

Step-by-step explanation:

Hello,

First of all, let's notice that even if we do not know the zeros of P(x) we can say that

$(1) \ \alpha + \beta =\dfrac{5}{6} \\ \\ (2) \ \alpha * \beta =\dfrac{k}{6}$

But, why !?

As they are the zeros of P(x), we can write:

$P(x)=6(x^2-\boxed{\dfrac{5}{6}}x+\boxed{\dfrac{k}{6}})=6(x-\alpha)(x-\beta)=6(x^2-\boxed{(\alpha +\beta)}x+ \boxed{\alpha *\beta} )$

And then we can identify the coefficients of the like terms to find the equations (1) and (2).

Now, we have one more equation which is:

$(3) \ \alpha -\beta =\dfrac{1}{6}$

(1)+(3) gives:

$\alpha + \beta +\alpha -\beta =\dfrac{5}{6}+\dfrac{1}{6}=\dfrac{6}{6}=1 \\ \\ 2\alpha =1 \ \text{ divide by 2 } \\ \\ \alpha =\dfrac{1}{2}$

And we replace in (3) to get the value of the second zero.

$\beta = \dfrac{1}{2}-\dfrac{1}{6}=\dfrac{3-1}{6}=\dfrac{2}{6}=\dfrac{1}{3}$

And, finally, from (2), it comes:

$k=6*\alpha *\beta =6*\dfrac{1}{2}*\dfrac{1}{3}=\dfrac{6}{6}=1$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

8 0

3 years ago