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Marrrta [24]
2 years ago
13

Find the slope and y-intercept of a line through the points (-3, -4) and (0, -1).

Mathematics
2 answers:
KonstantinChe [14]2 years ago
8 0
I have the same question 37377 not the
lions [1.4K]2 years ago
7 0

Answer:

The slope is 1 and the y-intercept is -1.

Step-by-step explanation:

\frac{y{2} }{x[2] } -\frac{y_{1} }{x_{1} }

Then plug in the numbers:

\frac{-1}{0} -\frac{-4}{3}

And then solve it: you'll get \frac{3}{3}= 1.

And the y-intercept is -1.

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Step-by-step explanation:

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Solve this problem on paper using all four steps. Enter each answer separated by a comma, in numerical order.
salantis [7]

Answer:

  • 27, 28, 29 and 30

Step-by-step explanation:

<u>Let the integers be:</u>

  • n, n + 1, n + 2 and n + 3

<u>Their sum is 114:</u>

  • n + n + 1 + n + 2 + n + 3 = 114

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<u>The numbers are:</u> 27, 28, 29 and 30

4 0
3 years ago
What is the slope of the line through (-1,8) and (3,-4)?
laila [671]

Hey there!!

How do we find slopes ?

Slope = \frac{y2-y1}{x2-x1}

We are given with two co-ordinates :

(-1,8) and (3,-4)  

Hence, the slope is :

\frac{-4-8}{3+1}

... \frac{-12}{4} = -3

The slope is -3.

Hope my answer helps!

4 0
3 years ago
Consider the linear equation 2x - 3y = -12 graph the points
levacccp [35]

The graph of linear equation 2x - 3y = -12 is as shown below.

I this question, we have been given a linear equation 2x - 3y = -12

We need to graph the points.

For x = 1,

2(1) - 3y = -12

2 - 3y = -12

-3y = -14

y = 14/3

For x = 0,

2(0) - 3y = -12

y = (-12)/(-3)

y = 4

For x = -1,

2(-1) - 3y = -12

-3y = -12 + 2

y = (-10) / (-3)

y = 10/3

So, we get coordinates (1, 14/3), (0, 4) and (-1, 10/3)

Now we plot these points.

The graph of linear equation 2x - 3y = -12 is as shown below.

Learn more about the linear equation here:

brainly.com/question/23832475

#SPJ1

4 0
1 year ago
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