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Marrrta [24]
3 years ago
13

Find the slope and y-intercept of a line through the points (-3, -4) and (0, -1).

Mathematics
2 answers:
KonstantinChe [14]3 years ago
8 0
I have the same question 37377 not the
lions [1.4K]3 years ago
7 0

Answer:

The slope is 1 and the y-intercept is -1.

Step-by-step explanation:

\frac{y{2} }{x[2] } -\frac{y_{1} }{x_{1} }

Then plug in the numbers:

\frac{-1}{0} -\frac{-4}{3}

And then solve it: you'll get \frac{3}{3}= 1.

And the y-intercept is -1.

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morpeh [17]

85+92+84+71+94+x /6>86

Multiply both sides by 6

426+x>516

Subtract 426 from both sides

X>90

8 0
3 years ago
The local supermarket is selling melons at the price of 2 for 3.00. At this rate, what is the price for 5 melons?
svp [43]
2 melons for $3 
4 melons = $6 
1 melon is half of $3 = $1.50 
4 melons = $6 + $1.50 = $7.50 for 5 melons 
8 0
3 years ago
What is the measure of the missing angle in the figure below?
Aleks [24]
Sum of all interior angles in a triangle = 180
let missing angle = x

x + 144 + 13 = 180
x + 157 = 180
x = 23

answer
23 degrees
7 0
3 years ago
Read 2 more answers
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
A bag contains purple marbles and red marbles, 34 in total. The number of purple marbles is 2 more than 3 times the number of re
Irina-Kira [14]

Answer:

There are 26 purple marbles in the bag.

Step-by-step explanation:

Firstly, you have to make an expression in terms of x where x represent red marbles. Given that the question says purple marbles is 2 more than 3 times the number of red marbles. So the expression is :

Let red marbles = x,

purple = 2 + 3x

red = x

Next, given that the total marbles in the bag is 34 so you have to add both marbles together and solve the value of x :

2 + 3x + x = 34

4x = 32

x = 32 \div 4

x = 8

Lastly, you have to substitute the value of x into the expression of purple marbles :

Let x = 8,

purpe = 2 + 3(8)

purple = 26

7 0
3 years ago
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