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dalvyx [7]
3 years ago
5

17 friends to 19 friends The percent increase is

Mathematics
2 answers:
Vinvika [58]3 years ago
7 0

Answer:

2?

Step-by-step explanation:

kvv77 [185]3 years ago
3 0

Answer:

the increase is by 2

Step-by-step explanation:

You can add 17 plus 2 or subtract 17 from 19.

You might be interested in
Solve |x| &lt; 13<br> A. {-13, 13}<br> B. {x| -13&lt; x &lt; 13}<br> C. {x|x &lt; -13, x&gt; 13}
Gemiola [76]

Answer:

the solution for x will be given by  {x| -13 < x < 13}

Therefore the correct option is B.

Step-by-step explanation:

i) given that |x| < 13

ii) therefore x < 13 for positive values of x

iii) for negative values of x we have -x < 13

    therefore x > -13

iv) from ii) and iii) above we can conclude that the solution for x will be given by {x| -13 < x < 13}

Therefore the correct option is B.

7 0
3 years ago
Divide 794.1 by 7.61 Point round off your answer to two decimal places
dolphi86 [110]
<span>By dividing the two numbers we get 104.3495... Rounding this number to two decimal places means that we must keep just 2 digits after the "." symbol, and round the last one of them. In our case, 104.3495... becomes 104.35.</span>
5 0
3 years ago
What is -13/6 as a repeating decimal​
monitta

Answer:

-2.16 repeating

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

6 0
3 years ago
If you have 470 apples and the price is 67 apples how much is each apple
EleoNora [17]

Answer:

Each apples cost about $0.14

Step-by-step explanation:

cost / amount = price per piece

67 / 470 = 0.14

So every apple costs about $0.14

8 0
3 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
4 years ago
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