Y - 4x = 7...y = 4x + 7
now sub 4x + 7 in for y in the other equation
2y + 4x = 2
2(4x + 7) + 4x = 2
8x + 14 + 4x = 2
12x = 2 - 14
12x = - 12
x = -1
y - 4x = 7
y - 4(-1) = 7
y + 4 = 7
y = 7 - 4
y = 3
solution is : (-1,3)
The <span>Pythagorean Theorem tells us that
where c is the </span><span>hypotenuse and a and b are the other two sides. To solve for one of the shorter sides we need to rearrange:
We can then substitute known values, and solve:
</span>
Hello from MrBillDoesMath!
Answer:
Domain: x >=0 for both cases
Discussion:
Assuming we are dealing with real valued functions, the domain of
y = x^(1/2) +4
is the set of all "x" such that x>= 0 (so we are taking the square root of a positive, or zero, real number)
The domain of x^(1/2) +6 -7 is the same as for the last function and for the same reason.
Thank you,
MrB
Answer:
I think the answer is 8 rounding tho would be 10
Step-by-step explanation:
