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3 years ago

What is the answer to this problem? Thank you.

Mathematics

1 answer:

Nina [5.8K]3 years ago

4 0

Answer:

90 degrees

Step-by-step explanation:

Because AC is tangent to the circle at point C, the radius is perpendicular to the tangent line. This means that OAC = to 90 degrees

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Glenn budgets 1/6 of his weekly allowance for entertainment. Glenn's entertainment bill is 29. What is his weekly allowance?

Nadusha1986 [10]

For this case, as you've got 1/6th, this will then mean that you have to multiply the bill (29) by 6, therefore, giving you 174. Glenn's weekly allowance is $174

4 0

3 years ago

sabine and jack know that 1 kilogram = 2.2 pounds and 1 pound = 0.454 kilogram. they each write an expression to convert 50 poun

zzz [600]

Answer:

50 pounds = 22.7 kilograms

Step-by-step explanation:

Yes both are correct

Sabine :

2.2 pounds = 1 kilogram

1 pound = 1/ 2.2 kilogram = 0.454 kilogram

50 pounds = 50 * 0.454 =22.7 kilograms

5 0

3 years ago

Help me to prove the given below. Thank you in advance

sleet_krkn [62]

Answer:

Construct MO, where O is the midpoint of CG. (As shown in the attached figure)

(1) LM = MG //given, CM is the median to the hypotenuse

(2) CO = OG // construction

(3) MO is a mid-segment //(1), (2) , Definition of a mid-segment

(4) MO // LC //triangle mid-segment theorem

(5) ∠MOG ≅ ∠LCO // corresponding angles in two parallel lines intersected by a transversal line (CG)

(6) m∠LCO=90° //given, ΔLCG is a right triangle

(7) m∠MOG=90° //(5), (6), definition of congruent angles

(8) m∠MOC=180° – 90° = 90° // linear pair

(9) ∠MOG ≅ ∠MOC //(7),(8), definition of congruent angles

(10) MO=MO //common side, reflexive property of equality

(11) ΔMCO ≅ ΔMGO //(2), (9), (10) Side-Angle-Side postulate

(12) MC = MG // Corresponding sides in congruent triangles (CPCTC)

(13) MG= ½LG // Given, CM is the median to the hypotenuse

(15) MC = ½LG //(12) , (13), substitution

8 0

3 years ago

What is the equation of the circle with center (-6,7) that passes through the point (4,-2). A. (x+6)^2+(y-7)^2=181 B. (x-6)^2+(y

pychu [463]

The equation of a cricle passing through (h,h) and with radius r is
$(x-h)^2+(y-k)^2=r^2$
so

cente ris (-6,7) and passing through (4,-2)
$(x-(-6))^2+(y-7)^2=r^2$
$(x+6)^2+(y-7)^2=r^2$
subsitute (4,-2) to find r^2

$(4+6)^2+(-2-7)^2=r^2$
$(10)^2+(-9)^2=r^2$
$100+81=r^2$
$181=r^2$

so it is

$(x+6)^2+(y-7)^2=181$
A is the answer

3 0

3 years ago

8.4 = 3 x m what is the value of m

nataly862011 [7]

M= 2.8

Alternate form:

14/5 or 2 4/5

5 0

2 years ago