X=kevin
<span>y=steve </span>
<span>x+y=26 </span>
<span>x=4+y </span>
(4+y)+y=26
<span>-4 -4 </span>
<span>y+y=22 </span>
2y=22
<span>/2 /2
</span>
<span>y=11 </span>
<span>steve ran 11 miles</span>
-7,14,-28,<u>5</u><u>6</u><u>,</u><u>-</u><u>1</u><u>1</u><u>2</u>
an = a1(r)^n-1
a4 = -7(-2)^4-1
a4 = -7(-2)³
a4 = -7(-8)
a4 = 56
an = a1(r)^n-1
a5 = -7(-2)^5-1
a5 = -7(-2)⁴
a5 = -7(16)
a5 = -112
<h2>#CarryOnLearning</h2>
Answer:
281
Step-by-step explanation:
8 + 7(42–3) =
= 8 + 7(39)
= 8 + 273
= 281
Answer:
Infinitely many solutions
Step-by-step explanation:
Note that 2(2x+3y=12) is 4x+6y=24, which is the first equation. Therefore, by canceling the equations out, you have 0=0, which means whatever one side equals, the other side ALWAYS equals that.
Attached is a Venn diagram of your problem.
Knowing how many likes all three will help. You know that 10 students like all three.
Rock and Jazz only:
16 like rock and jazz while 10 like all three. To get how many like jazz only, subtract 10 from 16.
16-10 = 6
Rock and Classical only:
13 like rock and classical while 10 like all three. To get how many like jazz only, subtract 10 from 13.
13-10 = 3
Jazz and classical only:
12 like jazz and classical while 10 like all three. To get how many like jazz only, subtract 10 from 12.
12-10 = 2
Now with that data you fill up the 4 intersecting areas. To get the outer, just remember that all areas within a circle should add up to the first assumption.
27 rock
24 classical
28 Jazz
All numbers in the rock circle should add up to 27.
All numbers in the classical circle should add up to 24.
All numbers in the Jazz circle should add up to 28.
Rock:
3+10+6+x = 27
19+x=27
x = 27-19
x= 8
Classical:
3+10+2+x = 24
15 + x = 24
x = 24-15
x = 9
Jazz:
10+6+2+x = 28
18 + x = 28
x = 28 - 18
x = 10
In summary: 8 liked only Rock, 9 liked only Classical, 10 liked only Jazz.