Answer:
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Step-by-step explanation:
we are given height equation as
where
h is the height in feet of a Juggler's ball after t seconds
now, we can plug t=1.5
we can solve for h
So,
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Answer:
5 units²
Step-by-step explanation:
Area of the triangle = ½ × base × height
base = 2
height = 5
Plug in the values into the formula
Area = ½ × 2 × 5
Area = ½ × 10
Area = 5 units²
Answer:
- 3 and 69/70
Step-by-step explanation:
3 ÷ 5(6 × 7) - 4
3 ÷ 5(40) - 4
3 ÷ 210 - 4
1/70 ÷ 4
- 3 and 69/70
Answer:
P = 40.56 ft
Step-by-step explanation:
The figure is composed of a rectangle and half circle
The perimeter of the figure = the length of the borders round the figure
= W + 2L + ½(perimeter of full circle)
W = 8 ft
L = 10 ft
½(perimeter of circle) = ½(πd) = ½(3.14*8)
= 12.56 ft
Plug in the values
Perimeter of the figure = 8 + 2(10) + 12.56
= 8 + 20 + 12.56
= 40.56 ft
F(x)=x^3+2
we see the power is odd
the ends go in opsoite directions
we know that if the leadind coefient (number in front of highest power term) is positive, then odd powered polynomials go from bottom left to top right
and for even ones, it goes both up
for negative, odd ones go from top left to bottom right
for even, both go down
we gots
f(x)=1x^3+2
positive and odd, so it goes from bottom left to top right
as x approaches negative inifnity, y approaches negaitve infinity
as x approaches infinity, y approaches infinity
