12/7 simply exchange the denominator and the numerator
Exponential growth of the form:
F=Ar^t
F=100(1.22)^t
F(5)=100(1.22)^5
F(5)=270.27
F(5)=270 to the nearest frog...
....
1.22=r^12
r=1.22^(1/12)
F=100(1.22^(1/12)^t)
F=100(1.22^(t/12)) now it will produce monthly populations...
Say we did the same as before but instead of 5 years you have 60 months...
F(60)=100(1.22^(60/12))
F(60)=270 to the nearest frog... :P
Answer:
x^2\ 16 - y^2/9 = 1
step-by-step explanation:
soooo the equation for a hyperbola that is horizontal is x^2/a^2 - y^2/b^2 = 1
a hyperbola should always equal one so dont forget that when writing your equation becuase it is easy to forget.
it helps to graph this so you can see it better
to find a it is the distance from the center to the vertices which is 4 so in the equation you will write 16 becuase it is a^2
then you need to find b. to get b you have to figure out that c is the distance from the center to the foci which is 5 and it is all related to the plythagorm theorum becuase it forms a right triangle. so you do c^2 - a^2 = b^2
you get 9 for b^2 because 25-16=9 and so you put that in the equation
Bill's age = x
Eya's age = 3x - 5
Eya is 28
28 = 3x - 5
28 (+5) = 3x -5 (+5)
33 = 3x
33/3 = 3x/3
x = 11
Bill = x
x = 11
Bill is 11 years old
hope this helps
Answer:
B
Step-by-step explanation:
