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julsineya [31]
2 years ago
8

Please help in this!

Mathematics
2 answers:
vovikov84 [41]2 years ago
4 0

Step-by-step explanation:

Correct option is C)

41−

21+

19−

9

=

41−

21+

19−3

=

41−

21+

16

=

41−

21+4

=

41−

25

=

41−5

=

36

=6

Juli2301 [7.4K]2 years ago
4 0

\sqrt{41 -  \sqrt{21 +  \sqrt{19 -  \sqrt{9} } } }  \\  =  \sqrt{41 -  \sqrt{21 +  \sqrt{19 - 3} } }  \\  =  \sqrt{41 -  \sqrt{21 +  \sqrt{16} } }  \\  =  \sqrt{41 -  \sqrt{21 + 4 } }  \\  =  \sqrt{41 -  \sqrt{25} }  \\  =  \sqrt{41 - 5}  \\  =  \sqrt{36}  \\  = 6

<u>Answer:</u>

<u>a)</u><u> </u><u>6</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

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Musya8 [376]

Answer:

No, this is not a right triangle.

4 0
2 years ago
20. Based on student records, 25% of the students at a large high school have a
Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the  probability that the student has a GPA lower than 3.5 and is not taking any AP  classes is calculated as:

P(A'∩B') = 1 - P(A∪B)

it means that the students that have a GPA lower than 3.5 and are not taking any AP  classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled  in at least one AP class is 0.12

So, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.25 + 0.16 - 0.12

P(A∪B) = 0.29

Finally, P(A'∩B') is equal to:

P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

5 0
3 years ago
Read 2 more answers
Can somebody tell me what 365 times 45 is??
Veseljchak [2.6K]

Answer:

16,425

Step-by-step explanation:

For future references, I'd say use a calculator for multiplication or calculate on a piece of paper. :)

4 0
3 years ago
Read 2 more answers
Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the
ziro4ka [17]

Answer:

a) \frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}&#10;And in order to find the sample mean we just need to use this formula:&#10;[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

The Confidence interval is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and the critical values are:

\chi^2_{\alpha/2}=20.09

\chi^2_{1- \alpha/2}=1.65

And replacing into the formula for the interval we got:

\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}

363.90 \leq \sigma^2 \leq 4430.80

Now we just take square root on both sides of the interval and we got:

19.08 \leq \sigma \leq 66.56

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0
3 years ago
Evaluate the expression a + b for a = 2 and b = 11
Lesechka [4]

If a+b= 2+11 then your sum will be 13.

heres an example...

If you have eleven dollars and I give you 2 more you can simply count up 2 more from 11 leaving you at 13.


you're welcome.

4 0
2 years ago
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