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geniusboy [140]
2 years ago
13

Solve the system of equations by graphing, elimination or

Mathematics
1 answer:
vladimir1956 [14]2 years ago
8 0

Answer:

Solve the system of equations by graphing, elimination or

subod

Step-by-step explanation:

You might be interested in
What are the odds of choosing a red marble from a bag that contains two blue marbles, one green marble and four red marbles?
Ierofanga [76]

Answer:

4/7.

Step-by-step explanation:

This the question in which marbles have to be taken out of a bag. Odds in another word for probability.

Total number of marbles in the bag = 2 Blue + 1 Green + 4 Red = 7 marbles.

Required marbles = 3 red marbles.

Therefore:

P (a red marble is selected in the first attempt) = Red Marbles / Total Marbles.

P (a red marble is selected in the first attempt) = 4/7.

Therefore, the correct answer is 4/7!!!

8 0
3 years ago
2〖sen〗^2 x+3 senx+1=0
KonstantinChe [14]

2 sin²(<em>x</em>) + 3 sin(<em>x</em>) + 1 = 0

(2 sin(<em>x</em>) + 1) (sin(<em>x</em>) + 1) = 0

2 sin(<em>x</em>) + 1 = 0   OR   sin(<em>x</em>) + 1 = 0

sin(<em>x</em>) = -1/2   OR   sin(<em>x</em>) = -1

The first equation gives two solution sets,

<em>x</em> = sin⁻¹(-1/2) + 2<em>nπ</em> = -<em>π</em>/6 + 2<em>nπ</em>

<em>x</em> = <em>π</em> - sin⁻¹(-1/2) + 2<em>nπ</em> = 5<em>π</em>/6 + 2<em>nπ</em>

(where <em>n</em> is any integer), while the second equation gives

<em>x</em> = sin⁻¹(-1) + 2<em>nπ</em> = -<em>π</em>/2 + 2<em>nπ</em>

2 cot(<em>x</em>) sec(<em>x</em>) + 2 sec(<em>x</em>) + cot(<em>x</em>) + 1 = 0

2 sec(<em>x</em>) (cot(<em>x</em>) + 1) + cot(<em>x</em>) + 1 = 0

(2 sec(<em>x</em>) + 1) (cot(<em>x</em>) + 1) = 0

2 sec(<em>x</em>) + 1 = 0   OR   cot(<em>x</em>) + 1 = 0

sec(<em>x</em>) = -1/2   OR   cot(<em>x</em>) = -1

cos(<em>x</em>) = -2   OR   tan(<em>x</em>) = -1

The first equation has no (real) solutions, since -1 ≤ cos(<em>x</em>) ≤ 1 for all (real) <em>x</em>. The second equation gives

<em>x</em> = tan⁻¹(-1) + <em>nπ</em> = -<em>π</em>/4 + <em>nπ</em>

<em />

sin(<em>x</em>) cos²(<em>x</em>) = sin(<em>x</em>)

sin(<em>x</em>) cos²(<em>x</em>) - sin(<em>x</em>) = 0

sin(<em>x</em>) (cos²(<em>x</em>) - 1) = 0

sin(<em>x</em>) (-sin²(<em>x</em>)) = 0

sin³(<em>x</em>) = 0

sin(<em>x</em>) = 0

<em>x</em> = sin⁻¹(0) + 2<em>nπ</em> = 2<em>nπ</em>

<em />

2 cos²(<em>x</em>) + 2 sin(<em>x</em>) - 12 = 0

2 (1 - sin²(<em>x</em>)) + 2 sin(<em>x</em>) - 12 = 0

-2 sin²(<em>x</em>) + 2 sin(<em>x</em>) - 10 = 0

sin²(<em>x</em>) - sin(<em>x</em>) + 5 = 0

Using the quadratic formula, we get

sin(<em>x</em>) = (1 ± √(1 - 20)) / 2 = (1 ± √(-19)) / 2

but the square root contains a negative number, which means there is no real solution.

2 csc²(<em>x</em>) + cot²(<em>x</em>) - 3 = 0

2 (cot²(<em>x</em>) + 1) + cot²(<em>x</em>) - 3 = 0

3 cot²(<em>x</em>) - 1 = 0

cot²(<em>x</em>) = 1/3

tan²(<em>x</em>) = 3

tan(<em>x</em>) = ± √3

<em>x</em> = tan⁻¹(√3) + <em>nπ</em>  OR   <em>x</em> = tan⁻¹(-√3) + <em>nπ</em>

<em>x</em> = <em>π</em>/3 + <em>nπ</em>   OR   <em>x</em> = -<em>π</em>/3 + <em>nπ</em>

7 0
3 years ago
How do you construct a frequency distribution table using sturge’s approximation
artcher [175]

The steps to use to construct a frequency distribution table using sturge’s approximation is as below.

<h3>How to construct a frequency distribution table?</h3>

The steps to construct a frequency distribution table using Sturge's approximation are as follows;

Step 1: Find the range of the data: This is simply finding the difference between the largest and the smallest values.

Step 2; Take a decision on the approximate number of classes in which the given data are to be grouped. The formula for this is;

K = 1 + 3.322logN

where;

K= Number of classes

logN = Logarithm of the total number of observations.

Step 3; Determine the approximate class interval size: This is obtained by dividing the range of data by the number of classes and is denoted by h class interval size

Step 4; Locate the starting point: The lower class limit should take care of the smallest value in the raw data.

Step 5; Identify the remaining class boundaries: When you have gotten the lowest class boundary, then you can add the class interval size to the lower class boundary to get the upper class boundary.

Step 6; Distribute the data into respective classes:

Read more about  frequency distribution table at; brainly.com/question/27820465

#SPJ1

6 0
2 years ago
The line AB has the midpoint of (2,5) A has coordinates (1,7) find the coordinates of B
Pavel [41]

Answer:

Point B is at (3,3)

Step-by-step explanation:

the mid point is (2,5) and A is at (1,7)

first find the slope:

y1 - y2/x1 - x2

7 - 5/1 - 2

2/-1

-2/1

then go down 2 units and right 1 unit from (2,5):

(2 + 1, 5 - 2) => (3,3)

6 0
2 years ago
Three times a number increased by four is<br> less than -62.
klemol [59]

Answer: x<-22

Step-by-step explanation:

3x+4<-62

3x<-66

x<-22

6 0
3 years ago
Read 2 more answers
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