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mars1129 [50]
3 years ago
12

Solve for x. A) 0.9 B) 160 C) 10 D) 1.1

Mathematics
2 answers:
attashe74 [19]3 years ago
5 0
C because it’s 10 in most cases
creativ13 [48]3 years ago
3 0

Answer:

C .10

Step-by-step explanation:

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Carol estimates that she has a 4/5 probability of gaining a grade 4 in her exam and a 1/10 chance of a grade 3 to 1. If her esti
Nesterboy [21]

Answer:

yuyu

Step-by-step explanation:

6 0
3 years ago
A store sells 2 printers for every 5 computers. The store sells 40 computers. How many printers does the store sell? I also have
Alona [7]
Well the answer of how many printers does the store sell is 16
so it would be 2 8 16

5 0
3 years ago
Read 2 more answers
Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

5 0
3 years ago
Find the value of x. Round to the nearest tenth
VladimirAG [237]

Answer:

36.869 or 36.87

Step-by-step explanation:

first, you find which trig function you are using. in this case, tangent.

then, you put calculate the arctan(3/4) which is 36.96989765

7 0
2 years ago
What is the equation process to this question?
Andreyy89

The given equation is h(t)=-16t^2+80t+4 where h is the height, in feet, of a ball and t is the time, in seconds.

<u>Part a: The height of the ball when t = 2 seconds:</u>

The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation h(t)=-16t^2+80t+4, we get;

h(2)=-16(2)^2+80(2)+4

Simplifying the terms, we get;

h(2)=-64+160+4

h(2)=100

Thus, the height of the ball after 2 seconds is 100 feet.

<u>Part b: The height of the ball when t = 4 seconds:</u>

The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation h(t)=-16t^2+80t+4, we get;

h(4)=-16(4)^2+80(4)+4

Simplifying the terms, we get;

h(4)=-256+320+4

h(4)=68

Thus, the height of the ball after 4 seconds is 68 feet.

5 0
3 years ago
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