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shusha [124]
2 years ago
7

Which measure of central tendency is the most affected by outliers

Mathematics
1 answer:
aliina [53]2 years ago
7 0

Mean measure of central tendency is the most affected by outliers. Then the correct option is B.

<h3>What is Mean?</h3>

The mean is the straightforward meaning of the normal of a lot of numbers. In measurements, one of the markers of focal propensity is the mean. The normal is alluded to as the number-crunching mean. It's the proportion of the number of genuine perceptions to the absolute number of perceptions.

Mean measure of central tendency is the most affected by outliers.

Then the correct option is B.

More about the mean link is given below.

brainly.com/question/521501

#SPJ1

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Slope of (-7,-2) (9,4)
Olenka [21]

Answer:

m= \frac{3}{8}

Step-by-step explanation:

1. Use the slope equation to solve the problem

\frac{y_{2} -y_{1}}{x_{2} -x_{1} }

2. Plug in your values into the equation.

\frac{4-(-2)}{9-(-7)}

3. Simplify the equation.

m= \frac{3}{8}

4 0
3 years ago
Find the product.
4vir4ik [10]
Answer :

6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}

Step-by-step explanation :

To find the product of

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)

we now apply the law of indices

{a}^{m} \times {a}^{n} = {a}^{m+n}

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}
3 0
2 years ago
A number minus 11 is 12.
Setler79 [48]

Let n = a number.

n - 11 = 12

n = 12 + 11

n = 23

5 0
2 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
3 years ago
What is 3 tens plus 7 tenths plus 8 hundredths as a decimal
Novay_Z [31]
3 tens= 30
7 tenths= 0.7
8 hundredths= 0.08

so 30+ 0.7+0.08= 30.78
4 0
3 years ago
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