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Citrus2011 [14]
3 years ago
10

Find the radius of both circles. Then describe the transformation/s needed to prove circle A

Mathematics
1 answer:
loris [4]3 years ago
5 0

Answer:

radius a: 1

radius b: 2

hope this maybe helps :)

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Devaughn's age is three times Sydney's age. The sum of their ages is 84 . What is Sydney's age?
defon

the answer is 21 years old

4 0
4 years ago
Find the true measurements of the missing angle and show your work
Wittaler [7]

Answer:

Angle = 45

Step-by-step explanation:

It is half of a right angle also (x = 15) :)

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3 years ago
A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

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4 years ago
Solve for x: 4/5x + 4/3 = 2x
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The answer is x=10/9
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3 years ago
Read 2 more answers
6. Camille is a first year accountant and a recent college graduate. She is paid a salary
Marina CMI [18]

jk ima awnser in one sec

4 0
3 years ago
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