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natali 33 [55]
3 years ago
8

HURRRYYYYYYYYY!!!!!!!1 WILL MARK BRAINLIEST

Mathematics
2 answers:
MaRussiya [10]3 years ago
7 0

Answer:

0.2

Step-by-step explanation:

15450÷15000

0.2 this is the answer

Maksim231197 [3]3 years ago
4 0

Answer:

I think It's actually 0.6%

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Help please please help pl33ze
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it is B

Step-by-step explanation:

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3 years ago
Which of the following can be divided by 3, with no remainder?
Nuetrik [128]

Answer:

A) 555

Step-by-step explanation:

555/3 = 185

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6 0
3 years ago
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Find the equation of a line that is perpendicular to the line y=(1/3)x+4 and contains the point (-9,0)?
torisob [31]

Answer:

y = -3x - 27

Step-by-step explanation:

0 = -3[-9] + b

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y = -3x - 27

* Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>]:

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4 years ago
Which measurement is most accurate to describe the amount that a teacup can hold?
Bingel [31]
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8 0
4 years ago
Which equation represents a hyperbola with a center at (0, 0), a vertex at (−48, 0), and a focus at (50, 0)?
Lerok [7]

bearing in mind that "a" is the length of the traverse axis, and "c" is the distance from the center to either foci.

we know the center is at (0,0), we know there's a vertex at (-48,0), from the origin to -48, that's 48 units flat, meaning, the hyperbola is a horizontal one running over the x-axis whose a = 48.

we also know there's a focus point at (50,0), that's 50 units from the center, namely c = 50.


\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2}\\ \textit{asymptotes}\quad y= k\pm \cfrac{b}{a}(x- h) \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \begin{cases} h=0\\ k=0\\ a=48\\ c=50 \end{cases}\implies \cfrac{(x-0)^2}{48^2}-\cfrac{(y-0)^2}{b^2}=1 \\\\\\ c=\sqrt{a^2+b^2}\implies \sqrt{c^2-a^2}=b\implies \sqrt{50^2-48^2}=b \\\\\\ \sqrt{196}=b\implies 14=b~\hspace{3.5em}\cfrac{(x-0)^2}{48^2}-\cfrac{(y-0)^2}{14^2}=1\implies \cfrac{x^2}{48^2}-\cfrac{y^2}{14^2}=1

8 0
3 years ago
Read 2 more answers
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