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eduard
3 years ago
12

Find the equation of a line that is perpendicular to the line y=(1/3)x+4 and contains the point (-9,0)?

Mathematics
1 answer:
torisob [31]3 years ago
7 0

Answer:

y = -3x - 27

Step-by-step explanation:

0 = -3[-9] + b

-27 = b

y = -3x - 27

* Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>]:

⅓ → -3

I am joyous to assist you anytime.

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Please Help! Multiple Choice!
Katyanochek1 [597]

Using the z-distribution, the p-value would be given as follows:

b) 0.0086.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis we test if the means are equal, hence:

H_0: \mu_D - \mu_C = 0

At the alternative hypothesis, it is tested if they are different, hence:

H_1: \mu_D - \mu_C \neq 0

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

  • \mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086
  • \mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556

Hence, for the distribution of differences, they are given by:

  • \overline{x} = 12 - 14 = -2.
  • s = \sqrt{0.6086^2 + 0.4556^2} = 0.76

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

z = \frac{\overline{x} - \mu}{s}

z = \frac{-2 - 0}{0.76}

z = -2.63.

Using a z-distribution calculator, for a two-tailed test, with z = -2.63, the p-value is of 0.0086.

Hence option B is correct.

More can be learned about the z-distribution at brainly.com/question/13873630

#SPJ1

4 0
2 years ago
. Which ordered pairs in the form (x, y) are solutions to the equation 7x – 5y = 28?
Brut [27]

we know that

If a ordered pair (x,y) is a solution of the equation, then the ordered pair must satisfy the equation

we have the equation

7x-5y=28

Let's verify all the cases to determine the solution to the problem.

<u>case A)</u> point (-6,-14)

Substitute the values of x and y in the equation

x=-6\\y=-14

7(-6)-5(-14)=28

-42+70=28

28=28 -------> is  true

therefore

The point  (-6,-14) is a solution of the equation

<u>case B)</u> point (-1,-7)

Substitute the values of x and y in the equation

x=-1\\y=-7

7(-1)-5(-7)=28

-7+35=28

28=28 -------> is  true

therefore

The point  (-1,-7) is  a solution of the equation

<u>case C)</u> point (4,10)

Substitute the values of x and y in the equation

x=4\\y=10

7(4)-5(10)=28

28-50=28

-22=28 -------> is not true

therefore

The point (4,10) is not a solution of the equation

<u>case D)</u> point (7,9)

Substitute the values of x and y in the equation

x=7\\y=9

7(7)-5(9)=28

49-45=28

4=28 -------> is not true

therefore

The point  (7,9) is not a solution of the equation

therefore

<u>the answer is </u>

(-6,-14)

(-1,-7)

8 0
3 years ago
Read 2 more answers
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kifflom [539]

Answer:

the answer is 15/14 when you add them

7 0
2 years ago
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Can someone help me with these 3 questions. Sorry for the annoyance.
erastova [34]

Answer:

the first one is 37

the second one is 36

the third one is 27

Step-by-step explanation:

4 0
2 years ago
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A line has equation y=x−5. The line is shifted 3 units to the left and 1 unit up. Which points are on the graph of the line afte
Katyanochek1 [597]
This is one way to do it

5 0
3 years ago
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