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Vsevolod [243]
2 years ago
13

CAN SOMEONE HELP ME PLZZ

Mathematics
2 answers:
const2013 [10]2 years ago
6 0

Answer:

C

Step-by-step explanation:

aalyn [17]2 years ago
3 0

Answer:

divide by 12

Step-by-step explanation:

12 +12=24

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Pls help me .question no 14
Alex_Xolod [135]

Question 14, Part (i)

Focus on quadrilateral ABCD. The interior angles add to 360 (this is true for any quadrilateral), so,

A+B+C+D = 360

A+90+C+90 = 360

A+C+180 = 360

A+C = 360-180

A+C = 180

Since angles A and C add to 180, this shows they are supplementary. This is the same as saying angles 2 and 3 are supplementary.

==================================================

Question 14, Part (ii)

Let

x = measure of angle 1

y = measure of angle 2

z = measure of angle 3

Back in part (i) above, we showed that y + z = 180

Note that angles 1 and 2 are adjacent to form a straight line, so we can say

x+y = 180

-------

We have the two equations x+y = 180 and y+z = 180 to form this system of equations

\begin{cases}x+y = 180\\y+z = 180\end{cases}

Which is really the same as this system

\begin{cases}x+y+0 = 180\\0+y+z = 180\end{cases}

The 0s help align the y terms up. Subtracting straight down leads to the equation x-z = 0 and we can solve to get x = z. Therefore showing that angle 1 and angle 3 are congruent. We could also use the substitution rule to end up with x = z as well.

4 0
3 years ago
What is (c+1) +9 in simplified form plz help
Afina-wow [57]
=(c+1)+9
=C+1+9
=C+10
10c
7 0
3 years ago
Read 2 more answers
PLEASE ANSWER THIS ALSO!!!​
svetoff [14.1K]

Answer:

option C. is correct answer it is 2/5

6 0
3 years ago
Read 2 more answers
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
In a​ lottery, the top cash prize was ​$642 ​million, going to three lucky winners. Players pick five different numbers from 1 t
kramer

Answer:

\frac{10}{53 \times 46 \times 26}

Step-by-step explanation:

The probability of matching the number drawn on the gold ball is

\frac{1}{46}

The number of possible pairs of numbers from 1 to 53 is

\binom{53}{2}  =  \frac{53 \times 52}{2}  = 53 \times 26

Choosing 5 numbers, you are choosing 10 different pairs:

\binom{5}{2}  =  \frac{5 \times 4}{2}  = 10

Therefore the probability of correctly matching the drawn pair is

\frac{10}{53 \times 26}

Thus, the probability of winning (matching the pair AND the gold ball) is

\frac{10}{53 \times 46 \times 26}

4 0
3 years ago
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