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Ainat [17]
3 years ago
8

Topic: Graphs.1.) Bob loves foreign languages and wants to plan his courseschedule for the following years. He is interested in

the followingnine language courses: LA15, LA16, LA22, LA31, LA32, LA126, LA127,LA141, and LA 169. The course prerequisites are.i.) LA15: (None)ii.) LA16: LA 15iii.) LA22: (None)iv.) LA31:LA 15v.) LA32:LA16, LA31vi.) LA126: LA22, LA32vii.) LA127: LA 16viii.) LA141:LA22, LA 16ix.) LA 169: LA32.Find the sequence of courses that allows Bob to satisfy allthe prerequisites.
Computers and Technology
1 answer:
saveliy_v [14]3 years ago
5 0

Answer:

  LA15; LA22

LA16; LA31; LA32

  LA169; LA126;

  LA127; LA141

Explanation:

Given

Courses: LA15,\ LA16,\ LA22,\ LA31,\ LA32,\ LA126,\ LA127,\ LA141,\ LA 169.

Required

Course sequence to satisfy the prerequisite

From the course prerequisite, we have:

1.\ LA15 \to None    and    3.\ LA22 \to None

This means that LA15 and LA22 are the base courses, and they have no prerequisite. So, we have:

[LA15; LA22]

LA16 and LA31 have LA15 as their direct course prerequisite. So, the sequence becomes

[LA15 \to [LA16, LA31]; LA22]

To complete the sequence, we read each course and place them other their prerequisite.

<em>See attachment for complete tree</em>

<em></em>

From the tree, we have the sequence to be:

<em>LA15; LA22</em>

<em>LA16; LA31; LA32</em>

<em>LA169; LA126;</em>

<em>LA127; LA141</em>

<em />

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#include<stdio.h>

      int main()

    {    

          int i=0,count=0;

          char data[50];

          printf("Enter the Bits: ");

          scanf("%s",data);            //entering the bits ie. 0,1  

          printf("Data Bits Before Bit Stuffing:%s",databits);

          printf("\nData Bits After Bit stuffing :");

          for(i=0; i<strlen(data); i++)

              {

              if(data[i]=='1')

                     count++;

              else

                     count=0;

                printf("%c",data[i]);

             if(count==4)

                {

                          printf("0");

                          count=0;

                 }

             }

    return 0;

 }

Explanation:

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