Answer:
A. dict = {‘Name’: ‘Matthew’, ‘Age’: 14, ‘School’: ‘ABC School’}
Explanation:
Since <em>python does not use type when declaring a variable</em>, you must make sure you make your variables correctly or else it won't compile correctly. Lists use braces[]; Strings use quotes, "" or ''; Integers are just declared with a number(s); Dictionaries use brackets{} and inside are <u>attributes of something</u>. For instance, you can use dictionaries to describe ages, {'"Bryan": 6, "Alex": 13, etc.} <u>Sort of like a json file</u>. Dictionaries also tend to use <u>uppercase letters</u> when describing something. The only answer that has all the attributes correct is A. dict = {‘Name’: ‘Matthew’, ‘Age’: 14, ‘School’: ‘ABC School’}
hope i helped :D
Answer:
Port scan targeting 192.168.1.106.
Explanation:
In the following question, there is some part of the question and options is missing.
In the following statement, when a file log is taken from the computer system which has Internet Protocol address is given in the statement and by the further details of the statement in which time and the port destination by examine those details of the Internet Protocol, the following port scan targeting the IP address 192.168.1.106.
Answer:
#include <iostream>
using namespace std;
int main()
{
char str[100][20];
int n;
cout<<"Strings you want to enter"<<endl;
cin>>n;
cout<<"enter n strings"<<endl;
for(int i=0;i<n;i++)
cin>>str[i];
for(int i=0;i<n;i++)
{
if((int)str[i][0]==98) //ascii value b is 98
cout<<str[i]<<endl;
}
return 0;
}
Explanation:
The above written code is for printing the strings which starts with the letter b.
To check if the string starts with a letter b we are checking the ascii value 98 which corresponds to b and then printing those strings.
Answer:
Because they think you're purple guy who killed them they tryna get revenge and stuff you in a suit like what happened to them
Explanation:
