Answer:
Part a) 
Part b) 
Part c) 
Part d) 
Step-by-step explanation:
see the attached figure to better understand the question
we know that
To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor
Part a) we have
The scale factor is 5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is
Part b) we have
The scale factor is 3.7
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is
Part c) we have
The scale factor is 1/5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is
Part d) we have
The scale factor is s
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is
Answer: 64
Step-by-step explanation:
If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.
EJ = JG
4w + 4 = 2w + 18
Subtract 2w from both sides
2w + 4 = 18
Subtract 4 from both sides
2w = 14
Divide both sides by 2
w = 7
EG = EJ + JG
EG = 4w + 4 + 2w + 18
EG = 6w + 22
Now that we know what 'w' is, we can substitute it for 7
EG = 6 (7) + 22
EG = 42 + 22 = 64
The measure of EG is 64.
Hope that helped!
Danville,Keflavik,Somerville,Ulsan,,Smithfield
Answer & Step-by-step explanation:
The diameter of the circle is 8 m and the radius of the circle is 4 units. So, now we have to plug in the numbers so we can find the circumference and the area of the circle.
So, the circumference of the circle is 25.12 m.
So, the area of the circle is 50.24 units².
9514 1404 393
Answer:
![\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26-2%5C%5C0%26-3%265%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The rotation matrix for 90° CCW is ...
![\left[\begin{array}{cc}0&-1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
Then the rotated coordinates are ...
![\left[\begin{array}{ccc}0&-1\\1&0\end{array}\right]\cdot\left[\begin{array}{ccc}0&-3&5\\0&1&2\end{array}\right]=\left[\begin{array}{ccc}0&-1&-2\\0&-3&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-3%265%5C%5C0%261%262%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-1%26-2%5C%5C0%26-3%265%5Cend%7Barray%7D%5Cright%5D)
_____
The transformation of each ordered pair is ...
(x, y) ⇒ (-y, x)
