Part II: Constructed Response (2 pt)

Mathematics

1 answer:

alekssr [168]2 years ago

5 0

Answer:

here hereh ehreh ehe

Step-by-step explanation:

You might be interested in

Solve for u. u+1/4=-4/5

DedPeter [7]

Answer:

u = (-21)/20

Step-by-step explanation:

Solve for u:

u + 1/4 = (-4)/5

Put each term in u + 1/4 over the common denominator 4: u + 1/4 = (4 u)/4 + 1/4:

(4 u)/4 + 1/4 = -4/5

(4 u)/4 + 1/4 = (4 u + 1)/4:

1/4 (4 u + 1) = -4/5

Multiply both sides of (4 u + 1)/4 = (-4)/5 by 4:

(4 (4 u + 1))/4 = (-4)/5×4

4×(-4)/5 = (4 (-4))/5:

(4 (4 u + 1))/4 = (-4×4)/5

(4 (4 u + 1))/4 = 4/4×(4 u + 1) = 4 u + 1:

4 u + 1 = (-4×4)/5

4 (-4) = -16:

4 u + 1 = (-16)/5

Subtract 1 from both sides:

4 u + (1 - 1) = (-16)/5 - 1

1 - 1 = 0:

4 u = (-16)/5 - 1

Put (-16)/5 - 1 over the common denominator 5. (-16)/5 - 1 = (-16)/5 - 5/5:

4 u = (-16)/5 - 5/5

-16/5 - 5/5 = (-16 - 5)/5:

4 u = (-16 - 5)/5

-16 - 5 = -21:

4 u = (-21)/5

Divide both sides by 4:

u = ((-21)/4)/5

5×4 = 20:

Answer: u = (-21)/20

3 0

3 years ago

Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.

statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$