Ask question

Ask question

All categories

2 years ago

11

Naomis diner sold 95 milkshakes last week 58 of the milkshakes had whip cream on top what percentage of the milkshakes had whipp

ed cream

1 answer:

Tpy6a [65]2 years ago

6 0

The answer is 63%
95/58= 637931 so you take the first 2 numbers

You might be interested in

Please help me on this im so overwhelmed right now

Allushta [10]

He hiked 15 miles on friday

3 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!!NEED HELP ASAP!! Carrie will spin the arrow on the spinner four times. What is the probability that the a

sladkih [1.3K]

The probability that the arrow will land on any of them <em>once</em> is 1/4.

The probability that the arrow will land on any of them <em>twice</em> is 1/4 * 1/4. This is because the probability of Event A <em>and</em> Event B is P(B) * P(A).

Based on this:

$P(a\cap b\cap c\cap d) = \frac{1}{4}\times \frac{1}{4}\times\frac{1}{4}\times\frac{1}{4}\\\\=\frac{1}{4\times4\times4\times 4}\\=\frac{1}{256}$

1/256

Hope this helps, let me know if I missed anything!

5 0

3 years ago

Read 2 more answers

Miss Gonzales opened an account with a deposit of $2,000,

Nesterboy [21]

Answer:

i think its 18%

8 0

2 years ago

A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5

liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

$Q(t) = Q(0)e^{rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that $Q(5730) = 0.5Q(0)$

So

$Q(t) = Q(0)e^{rt}$

$0.5Q(0) = Q(0)e^{5730r}$

$e^{5730r} = 0.5$

$\ln{e^{5730r}} = \ln{0.5}$

$5730r = \ln{0.5}$

$r = \frac{\ln{0.5}}{5730}$

$r = -0.00012$

So

$Q(t) = Q(0)e^{-0.00012t}$

How old is the fossil?

This is t for which

$Q(t) = 0.8Q(0)$

So

$Q(t) = Q(0)e^{-0.00012t}$

$0.8Q(0) = Q(0)e^{-0.00012t}$

$e^{-0.00012t} = 0.8$

$\ln{e^{-0.00012t}} = \ln{0.8}$

$-0.00012t = \ln{0.8}$

$t = -\frac{\ln{0.8}}{-0.00012}$

$t = 1860$

The fossil is 1860 years old.

4 0

2 years ago

An animal gained 5 kilograms steadily over 20 years. What is the unit rate of kilograms per year?

balandron [24]

The unit rate is 0.25 kilograms per year.

Step-by-step explanation:

Lets define unit rate first

Unit rate is the change in quantity per unit time.

Given

Weight = w = 5 kg

Time = t = 20 years

So,

$Unit\ rate = \frac{weight}{time}\\=\frac{w}{t}\\= \frac{5}{20}\\= 0.25$

Hence,

The unit rate is 0.25 kilograms per year.

Keywords: Unit rate, rate of change

Learn more about unit rate at:

#LearnwithBrainly

5 0

2 years ago