Find four consecutive integers whose sum is 290.
2 answers:
For an instance, n is the smallest number, then the other number will be (n + 1), (n + 2), (n + 3)
Write an equation based on the problem
the sum of the numbers = 290
n + n + 1 + n + 2 + n + 3 = 290
4n + 6 = 290
<em>This is the equation</em>
Solve the equation
4n + 6 = 290
4n = 290 - 6
4n = 284
n = 284/4
n = 71
The smallest number is 71
Find the other three numbers
n + 1 = 71 + 1 = 72
n + 2 = 71 + 2 = 73
n + 3 = 71 + 3 = 74
The other numbers area 72,73,74
n = number
(n + 1) + (n + 2) + (n + 3) + (n + 4) = 290
⬇️
4n + 10 = 290
4n = 280
n = 70
⬇️
70 + 1 = 71
70 + 2 = 72
70 + 3 = 73
70 + 4 = 74
⬇️
The numbers are 71, 72, 73, and 74
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You have to subtract 4 from 7 and then add 5 and 3 then add 8 and 2 then multiply 10 with 3 to get 30.
Answer:
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Step-by-step explanation:
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