Find four consecutive integers whose sum is 290.

2 answers:

8 0

For an instance, n is the smallest number, then the other number will be (n + 1), (n + 2), (n + 3)

Write an equation based on the problem
the sum of the numbers = 290
n + n + 1 + n + 2 + n + 3 = 290
4n + 6 = 290
This is the equation

Solve the equation
4n + 6 = 290
4n = 290 - 6
4n = 284
n = 284/4
n = 71
The smallest number is 71

Find the other three numbers
n + 1 = 71 + 1 = 72
n + 2 = 71 + 2 = 73
n + 3 = 71 + 3 = 74
The other numbers area 72,73,74

jarptica [38.1K]3 years ago

3 0

n = number

(n + 1) + (n + 2) + (n + 3) + (n + 4) = 290

⬇️

4n + 10 = 290

4n = 280

n = 70

⬇️

70 + 1 = 71
70 + 2 = 72
70 + 3 = 73
70 + 4 = 74

⬇️

The numbers are 71, 72, 73, and 74

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