Find four consecutive integers whose sum is 290.
2 answers:
For an instance, n is the smallest number, then the other number will be (n + 1), (n + 2), (n + 3)Write an equation based on the problem the sum of the numbers = 290 n + n + 1 + n + 2 + n + 3 = 2904n + 6 = 290 <em>This is the equation</em>Solve the equation 4n + 6 = 290 4n = 290 - 6 4n = 284 n = 284/4 n = 71The smallest number is 71 Find the other three numbers n + 1 = 71 + 1 = 72 n + 2 = 71 + 2 = 73 n + 3 = 71 + 3 = 74The other numbers area 72,73,74
n = number (n + 1) + (n + 2) + (n + 3) + (n + 4) = 290 ⬇️ 4n + 10 = 290 4n = 280 n = 70 ⬇️ 70 + 1 = 71 70 + 2 = 72 70 + 3 = 73 70 + 4 = 74 ⬇️ The numbers are 71, 72, 73, and 74
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