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nasty-shy [4]
4 years ago
5

Twelve athletes are running a race. A gold medal is to be given to the winner, a silver medal is to be given to the second-place

finisher, and a bronze medal is to be given to the third-place finisher. Assume that there are no ties. In how many possible ways can the 3 medals be distributed?
Mathematics
1 answer:
kykrilka [37]4 years ago
8 0

Answer:

1320

Step-by-step explanation:

We are given that

Total number of athelets are running in race=12

Total number of medals =3

We have to find the total possible number of ways can the 3 medals be distributed.

Total number of ways for choosen gold medal=12

Number of ways for choosen silver medal=11

Number of ways for choosen Bronze medal=10

Total number of possible ways=12\times 11\times 10=1320

Hence, total number of possible ways in which  3 medals be distributed=1320

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Answer: 3x + 3 = 2x + 1

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Step-by-step explanation:

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Softa [21]
180^o-112^o=68^o

\left\{\begin{array}{ccc}2x+3y=68&|\cdot(-15)\\30x+11y=112\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-30x-45y=-1020\\30x+11y=112\end{array}\right}\\.\ \ \ \ \ \ \ -34y=-908\ \ \ |:(-34)\\\\.\ \ \ \ \ \ \ \ \ \ \  y=\dfrac{908}{34}\to y=\dfrac{454}{17}\\\\2x+3\cdot\dfrac{454}{17}=68\ \ \ \ |\cdot17\\\\34x+1362=1156\ \ \ \ |-1362\\34x=-206\ \ \ \ |:34\\\\x=-\dfrac{206}{34}\to x=-\dfrac{103}{17}\\\\  \left\{\begin{array}{ccc}x=-\dfrac{103}{17}\\\\y=\dfrac{454}{17}\end{array}\right
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Step-by-step explanation:

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