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nasty-shy [4]
3 years ago
5

Twelve athletes are running a race. A gold medal is to be given to the winner, a silver medal is to be given to the second-place

finisher, and a bronze medal is to be given to the third-place finisher. Assume that there are no ties. In how many possible ways can the 3 medals be distributed?
Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

1320

Step-by-step explanation:

We are given that

Total number of athelets are running in race=12

Total number of medals =3

We have to find the total possible number of ways can the 3 medals be distributed.

Total number of ways for choosen gold medal=12

Number of ways for choosen silver medal=11

Number of ways for choosen Bronze medal=10

Total number of possible ways=12\times 11\times 10=1320

Hence, total number of possible ways in which  3 medals be distributed=1320

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Mr. Wayne uses his cell phone for work. He is reimbursed $45.95 each month. How much will Mr. Wayne himself pay for his family's
Ostrovityanka [42]

Answer:

$1654.20

Step-by-step explanation:

There are 12 months in a year. There are 36 months in 3 years. If he gets charged $45.95 each month for 3 years or 36 months, he pays:

$45.95×36=

$1654.20 for three years.

5 0
3 years ago
A frying pan has a circumference of 43.96 centimeters What is the radius of the frying pan? Use 3.14 for
LiRa [457]

Answer:

7

Step-by-step explanation:

43.96 divided by 3.14= 14 (diameter)

14 divided by 3= 7 (radius)

7 0
3 years ago
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
sdas [7]

Answer:

a

    n=  75, 582

b

  n=    2300

c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
3 years ago
julie buys 2kg of apples and 7kg of pears £12.70. the pears cost £1.30 per kilogram what is the price per kilogram of the apples
Maru [420]
1.44 per kg

take 1.3 x 2, then subtract 12.7, finally divide that by 7
4 0
3 years ago
Read 2 more answers
What is the value of x so that the line segment with endpoints W(x, −2) and X(5, −4) is parallel to the line segment with endpoi
professor190 [17]
Uhhhh I don't think that the correct answer.
First, find the gradient of the line segment.
Gradient = Rise/Run = (2-6)/(2-5) = 4/3.
Since the other line segment is parallel to this line segment, their gradients are the same.
That means (-2+4)/(x-5) = 4/3.
2/(x-5) = 4/3
It is obvious x = 6.5
7 0
3 years ago
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