Ask question

Ask question

All categories

3 years ago

9

What is the value of x so that the line segment with endpoints W(x, −2) and X(5, −4) is parallel to the line segment with endpoi

nts Y(2, 2) and Z(5, 6)?
x equals six start fraction one over two end fraction
x = 6
x equals three start fraction one over two end fraction
x = 7

1 answer:

professor190 [17]3 years ago

7 0

Uhhhh I don't think that the correct answer.
First, find the gradient of the line segment.
Gradient = Rise/Run = (2-6)/(2-5) = 4/3.
Since the other line segment is parallel to this line segment, their gradients are the same.
That means (-2+4)/(x-5) = 4/3.
2/(x-5) = 4/3
It is obvious x = 6.5

You might be interested in

Please answer CORRECTLY for brainliest guarantee. If your answer is not correct or does not have a explanation I will report you

Scorpion4ik [409]

Answer:

c. 45.34ft

Step-by-step explanation:

When leg one of the triangle is 15ft and leg two is 17 ft you would take 17^2 + 15^2 and then you find the square root of that (514) to get the hypotenuse of the triangle. After that you multiply by two to account for the 2/2 sqaure foot per each unit

4 0

3 years ago

5-2 ????=7-5 ???? which value of x is the solution to the above equation?

saw5 [17]

5-2x=7-5x
-2x+5x=7-5
3x=2
X=2/3

8 0

3 years ago

Choose the equation of the line that is parallel to the y- axis.

Alex17521 [72]

The answer is x=-2 because its the only one thats parallel to the y axis

8 0

2 years ago

Read 2 more answers

For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4

Elina [12.6K]

Answer:

<em>C.</em> $(5-\frac{1}{2})^6$

Step-by-step explanation:

Given

$15(5)^2(-\frac{1}{2})^4$

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

$Sum = 2 + 4$

$Sum = 6$

Each term of a binomial expansion are always of the form:

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

Where n = the sum above

$n = 6$

Compare $15(5)^2(-\frac{1}{2})^4$ to the above general form of binomial expansion

$(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......$

Substitute 6 for n

$(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......$

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

We have;

$^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4$

Further comparison gives

$^nC_r = 15$

$a^{n-r} =(5)^{6-4}$

$b^r= (-\frac{1}{2})^4$

[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

$a = 5$

$n = 6$

$r = 4$

[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

$r = 4$

$b = \frac{-1}{2}$

Substitute values for a, b, n and r in

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

$(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......$

Solve for $^6C_4$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em> $(5-\frac{1}{2})^6$ <em />

3 0

3 years ago

Joe has fraction 5 over 6 pound of bird seed. He needs Fraction 1 over 3. pound to feed the birds daily. Which of the rectangle

Studentka2010 [4]

I divided the two fractions & drew a model.

$\frac{5}{6}/ \frac{1}{3} = 2.5$

So we know that the bird seed will last 2.5 days.

Knowing this, we can go with:

B. Rectangle model divided into six equal sections, five sections are labeled five-sixths and two sections are labeled one-third, equaling two and one-half days.

Let me know if you find any problems with my answer.

9 0

3 years ago