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Nadusha1986 [10]
2 years ago
9

Help me find the scale factor​

Mathematics
1 answer:
atroni [7]2 years ago
3 0
The scale factor for the first one is 2.25
And for the second one it’s 7
I hope this helps :)
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A square has a diagonal length of 24 inches. What is the area of the square?
SIZIF [17.4K]
The answer is 576 in^2
3 0
3 years ago
A foam toy is 2 inches wide. It doubles in size for every minute it is in water. Write an expression for the width of the toy af
Solnce55 [7]

it would be 2(2^5), which is two times two to the fifth power. you take the original size and double it for every minute, which is like squaring it, but to the power of five, because it doubles once every minute for five minutes. i hope this makes sense!:)

7 0
3 years ago
The endpoint of a line segment is (-9, 7). The midpoint of the segment is (10, -3). Find the other endpoint. *show work*
slavikrds [6]
First we will find the x coordinate.

x1+x2 / 2 = the x coordinate of the midpoint.

-9 + x2 / 2 = 10
x2/2 -4.5 = 10
x2/2 = 14.5
x2 = 29

Now the y coordinate:

y1+y2 /2 = y coordinate of the midpoint

7 + y2 / 2 = -3
y2/2 + 3.5 = -3
y2/2 = -6.5
y2 = -13

So the other endpoint is (29,-13)

I hope i am right :)

8 0
3 years ago
NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
Read 2 more answers
6. net<br> 28 in.<br> 2.5 in.<br> Surface area
ExtremeBDS [4]

Answer:

28

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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