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3 years ago

How you to transform a polynomial equation in standard form? state some steps

Mathematics

1 answer:

frez [133]3 years ago

6 0

Answer:

A very common way to transform a polynomial equation in standard form is usually by writing a polynomial in its standard form.

This is mainly achieved by checking the degree of the terms involved and writing them in the order of degree which should follow the pattern of from highest to lowest, left to right.

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3x + 8 ≥ 11 what is the answer i dont feel like doing it

Archy [21]

Answer:

lol it's x ≥ 1

Step-by-step explanation:

3x + 8 ≥ 11

-8 -8

3x ≥ 3

x ≥ 1

that happens to me all the time

7 0

3 years ago

Read 2 more answers

Solve for x by using log. Rounded to hundredth. <br><br> <img src="https://tex.z-dn.net/?f=4%5E%7B2x-5%7D%20%3D6%5E%7B-x%2B1%7D"

wel

Answer: $x=1.91$

Step-by-step explanation:

Given the expression $4^{2x-5} =6^{-x+1}$ , apply logarithm to both sides. Then:

$log(4)^{2x-5} =log(6)^{-x+1}$

Remembert that according the the properties of logarithms:

$log(a)^n=nlog(a)$

Then:

$(2x-5)log(4)=(-x+1)log(6)$

Appy distributive property and solve for "x":

$2xlog(4)-5log(4)=-xlog(6)+log(6)\\2xlog(4)+xlog(6)=log(6)+5log(4)\\x(2log(4)+log(6))=log(6)+5log(4)\\\\x=\frac{log(6)+5log(4)}{2log(4)+log(6)}\\\\x=1.91$

6 0

4 years ago

Read 2 more answers

The math club is selling gift wrap for a fundraiser. They sold all 45 rolls of solid wrapping paper at $4 each and rolls of patt

Aliun [14]

They sold 17 rolls. If 45 were sold at $4 dollars then $4×45= 180 If they made 265 dollars so you have to subtract 180$265-180= 85 dollarsYou know the remainder were sold at $5 dollar and dividing 85÷5= 17

4 0

3 years ago

Let f (x) = 1/x<br> and g(x) = x² – 3x. What<br> two numbers are not in the domain of fºg?

iren [92.7K]

For this case we have the following equations:

$f (x) = \frac {1} {x}\\g (x) = x ^ 2-3x$

We must find $(f_ {o} g) (x):$

By definition of composition of functions we have to:

$(f_ {o} g) (x) = f (g (x))$

So:

$(f_ {o} g) (x) = \frac {1} {x ^ 2-3x}$

We must find the domain of f (g (x)). The domain will be given by the values for which the function is defined, that is, when the denominator is nonzero.

$x ^ 2-3x = 0\\x (x-3) = 0$

So, the roots are:

$x_ {1} = 0\\x_ {2} = 3$

The domain is given by all real numbers except 0 and 3.

Answer:

x other than 0 and 3

8 0

3 years ago

Read 2 more answers

The range of F(x) = logbx is the set of all positive real numbers.

shtirl [24]

Answer:

The range of F(x) = logbx is the set of all positive real numbers is TRUE

Step-by-step explanation:

Given:

A function which logarithmic i.e F(x)=logbX=logx/logb with base 10

To Find;

Range belongs to All set are positive real numbers.

Solution:

The domain is function for which all set of inputs are defined and range for function is that set of all output that functions takes.

So Simple logarithmic function y=logbX is

$X=b^y$

So The functions has domain of all real values and range set of all real number.

In general the function F(x) = logbx where X>0 and b≠1 is continuous and one to one function.

logarithmic function is not defined for negative numbers or for zero.

And Also function approaches y-axis as x-tends to infinity but never touches the it.

Hence the Given statement is true

7 0

4 years ago