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Gelneren [198K]
3 years ago
10

How you to transform a polynomial equation in standard form? state some steps

Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer:

A very common way to transform a polynomial equation in standard form is usually by writing a polynomial in its standard form.

This is mainly achieved by checking the degree of the terms involved and writing them in the order of degree which should follow the pattern of from highest to lowest, left to right.

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The median of a continuous random variable having distribution function F is that value m such that F(m) = 1/2 . That is, a rand
neonofarm [45]

Answer:

Step-by-step explanation:

To find median and mode for

a) In a uniform distribution median would be

(a+b)/2 and mode = any value

b) X is N

we know that in a normal bell shaped curve, mean = median = mode

Hence mode = median = \mu

c) Exponential with parameter lambda

Median = \frac{ln2}{\lambda }

Mode =0

7 0
3 years ago
Due today HELP PLEASEEEEE!!!
Deffense [45]

Answer:

Oiiiiio ka cha thik cha

4 0
3 years ago
Siri am I a mix of recipe that calls for 1 1/2 cups of flour and 3/4 to get butter Jeremiah uses three sticks of butter how many
Inga [223]

Answer:

6 cups

Step-by-step explanation:

jeremiah 4× the recipe

3/4×4=3

so 1 1/2×4=6

8 0
3 years ago
The formula below, Newton's law of cooling, allows us to calculate the temperature of an object as it cools. T = R + (T0 − R)e-k
trasher [3.6K]
The Newton`s law of cooling:
T = R + ( To - R ) * e ^(-kt )
We know that: T = 32° F ( the water freezes at 32° F ), To = 55° F, R = 5° F
and the cooling rate is:  k = 0.012.
33° F = 5° F + ( 55° F - 5° F ) · 2.72^(-0.012 t )
33 - 5 = 50 · 2.72^(-0.012 t)
27 = 50 · 2.72^(-0.012 t)
2.72^(-0.012 t) = 27/50
1 / 2.72^(0.012 t) = 0.54
2.72^( 0.012 t ) = 1 : 0.54 = 1.85
0.012 t = log(base e) 1.85 = ln 1.85 = 0.6
t = 0.6 : 0.012 = 50
Answer: It would take 50 minutes.
 

7 0
3 years ago
Read 2 more answers
What is the fifth square root of x^16
melamori03 [73]
The fifth square root as in a^(1/2)^(1/2)^(1/2)^(1/2)^(1/2)

Well that is equal to a^((1/2)^5) or a^(1/32)

Since a=x^16 in this case and the rule (b^a)^c=b^(a*c) we have:

(x^16)^(1/32)

x^(16/32)

x^(1/2) or if you prefer

√x


8 0
3 years ago
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