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3 years ago

Can someone please help me

Mathematics

2 answers:

Masteriza [31]3 years ago

5 0

Answer: 7 and 83

Step-by-step explanation:

complementary have an engles sum of 90 degree

7+83=90.

adell [148]3 years ago

4 0

7 and 83!!!!!!!!!!!!!!!!!!!!!!

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Help please!!!!!!!!!!!!!!!

Likurg_2 [28]

First, find the area of the whole square.

Area= Base times height= 48 times 96 = 4608

Next, find the area of ONE circle. The diameter is 12, so the radius would be 6

A=πr sqaured= 3.14 times 6 squared = 113.04

Next multiply by 3, since there are 3 circles.

113.04 times 3 =339.12

Subtract this value from the total area (4608)

4608-339.12=4268.88

ANSWER: 4268.88

8 0

3 years ago

The quotient of 24 and the sum of<br> -4 and<br> -8

pychu [463]

Answer:

0.75

Step-by-step explanation:

-4 x -8 = 32

24 divided by 32 = 0.75

6 0

3 years ago

What is the surface area of a cube that’s measured 8 inches

MrRa [10]

Answer:

Step-by-step explanation:

Haven't done this in awhile but I think it's 2 because if you cube 2 it comes to 8. L x W x H = 8 | 2 x 2 x 2 = 8

7 0

2 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

3 years ago

Hi pls help me ty in advance

Anna35 [415]

A right angle = 90 degrees

A round angle = 360 degrees

1. 3 x 90 = 270 degrees

2. 4 x 90 = 360 degrees

3. 1 1/2 x 90 = 135 degrees

4. 2 1/3 x 90 = 210 degrees

5. 2/9 x 360 = 80 degrees

6. 3 3/8 x 360 = 1,215 degrees

5 0

2 years ago