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kumpel [21]
3 years ago
15

At a certain conference the information technology session and the social media session occur at the same time so it is impossib

le for an attendee to sit in on both sessions. If the probability that an attendee sits in on the information technology session is 0.11, and the probability that an attendee sits in on the social media session is 0.62, what is the probability that an attendee sits in on the information technology session or the social media session?
Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

0.73 = 73% probability that an attendee sits in on the information technology session or the social media session.

Step-by-step explanation:

What is the probability that an attendee sits in on the information technology session or the social media session?

They cant be in both sections simultaneously, so this probability is the sum of each probability.

0.11 = 11% probability that an attendee sits in on the information technology session

0.62 = 62% probability that an attendee sits in on the social media session

0.11 + 0.62 = 0.73

0.73 = 73% probability that an attendee sits in on the information technology session or the social media session.

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Answer:

4. Find the Width by dividing 50 by 2. Then double the length, double the width, and add the products to find the perimeter = Yes

Step-by-step explanation:

The length of a rectangular dog park is 50 feet. The width is half the length.

The formula for Perimeter is given as:

P = 2L + 2W

Length = 50 feet

Width = 50 feet/2

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P = 2(50) + 2(25)

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Hence, writing yes or no in front of each step in the options.

1. Find the Width by dividing 50 by 2. Then add the length and width and multiply the sum to find the perimeter = No

2. Find the Width by dividing 50 by 2. Then multiply the length by the width to find the perimeter. = No

3. Find the Width by dividing 50 by 2. Then add the length and the width to find the perimeter.= No

4. Find the Width by dividing 50 by 2. Then double the length, double the width, and add the products to find the perimeter = Yes

5. Find the Width by dividing 50 by 2. Then add the sum of each length and the sum of each width to find the perimeter = No

THE CORRECT STEP IN THE ABOVE OPTION IS OPTION 4

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