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aalyn [17]
3 years ago
7

4 1/5 kg: 630 g simplify this question

Mathematics
1 answer:
Rashid [163]3 years ago
5 0

Answer: 2646kg

Hope this helps

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1.In a right triangle, <A and <B are acute. Find the value of csc A, when tan A = 8/15.
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Answer:

(1)csc A=\dfrac{17}{8}

(2)sec A=\dfrac{17}{15}

Step-by-step explanation:

<u />Tan A=\dfrac{8}{15}\\$In Trigonometry, $Tan A=\dfrac{Opposite}{Adjacent}\\$Therefore:\\Opposite=8, Adjacent=15<u />

Using Pythagoras theorem

Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=8^2+15^2\\Hypotenuse^2=289\\Hypotenuse^2=17^2\\Hypotenuse=17

<u>Question 1</u>

Now, cosecant = 1/sin

Therefore:

csc A=\dfrac{Hypotenuse}{Opposite}\\csc A=\dfrac{17}{8}

<u>Question 2</u>

Now, secant = 1/cos

Therefore:

sec A=\dfrac{Hypotenuse}{Adjacent}\\sec A=\dfrac{17}{15}

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