Question

13 percent of a certain company's life insurance policy holders are smokers. For each nonsmoker the probability of dying during the year is 0.002. For each smoker the probability of dying during the year is 0.02. Find the probability that a policy holder who died last year was a smoker.

Answer 1

Answer:

.6

Step-by-step explanation:

Using Bayes' theorem

While s = smoker

n = nonsmoker

D = died

P(s) = .13

P(n) =.87

P(D/s) =0.02

P(D/n) =0.002

P(s/D) = ??

$P(s/D)=\frac{P(s)*P(D/s)}{P(s)*P(D/s)+P(n) *P(D/n)} =\frac{.13*.02}{.13*.02+.87*.002}=.6$